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Nat2105 [25]
3 years ago
11

Two diamonds begin a free fall from rest and from the same height 1 second apart.

Physics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

Explanation:

let t be time since the second diamond is released

a) y = ½g(t + 1)²

b) y' = ½g(t)²

c)

25 = ½g(t + 1)² - ½gt²

25 = ½g(t² + 2t + 1) - ½gt²

25 = ½gt² + gt + ½g - ½gt²

25 = g(t + ½)

t + ½ = 25 / g

t = (25 / g) - ½

t = (25 / 9.8) - ½

t = 2.05102... ≈ 2.1 s

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