Calculate the mass of magnesium needed to make 25g of magnesium oxide

Since the number of atoms in a substance is so large , a unit to count them was created. This unit is the number of atoms in 12

larisa86 [58]

The number of atoms in one mole of any substance is measured by Avogadro's number. The value of Avogadro's number is 6.023 x 10 ^23. It is named after scientist Avogadro who proposed this number. 12 grams of carbon-12 represents 1 mole of carbon-12. For this reason, the number of atoms present in 1 mole of any substance is 6.023 x 10 ^23. Therefore, the number of atoms present in 1 mole carbon-12 is 6.023 x 10^23.

(Answer) This unit is the number of atoms in 12 grams of carbon-12 and known as Avogadro's number.

7 0

3 years ago

If a clot were made up of a mass of proteins, what change in the proteins led to the formation of a clot?

S_A_V [24]

Answer: The proteins were no longer soluble in the blood.

3 0

3 years ago

Write the balanced chemical equation for the following reaction. Phases are optional. Solid calcium chlorate decomposes to form

Tanya [424]

Answer:

Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Explanation:

1) Word equation (given)

calcium chlorate (solid) → solid calcium chloride (solid) + oxygen (gas)

2) Chemical formulae of the reactant and products:

Calcium chlorate:

The most common oxidation states of chlorine are -1, +1, +3, +5, +7.

The suffix ate in chlorate means that chlorine atom is with the third lowest oxidation state (counting only the positive states). So, this is +5.

The oxidation state of calcium is +2.

Hence, the chemical formula of calcium chlorate is Ca(ClO₃)₂

Calcium chloride

The suffix ide in chloride means that chlorine is with oxidation state -1. Again the oxidation state of calcium is +2.

Hence, the chemical formula of calcium chloride is CaCl₂

Oxygen

Oxygen gas is a diatomic molecule, so its chemical formula is O₂.

Phases

The symbols s and g (in parenthesis) indicate the solid and gas phases respectively.

3) Chemical equation:

Ca(ClO₃)₂ (s) → CaCl₂ (s) + O₂ (g)

That equation is not balanced becasue the number of O atoms in the reactant side and in the product side are different.

4) Balanced chemical equation:

Add a 3 as coefficient in front of O₂(g), in the product side to balance:

Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Verify that all the atoms are balanced:

Atom Reactant side Product side

Ca 1 1

Cl 2 2

O 3×2 = 6 2×3 = 6

Conclusion: the equation is balanced and the final answer is:

Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

5 0

4 years ago

Give an example of gravitational potential

larisa86 [58]

A raised weight.

Water that is behind a dam.

Have a nice day!

4 0

3 years ago

Read 2 more answers

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

4 years ago

Calculate the mass of magnesium needed to make 25g of magnesium oxide​

Calculate the mass of magnesium needed to make 25g of magnesium oxide