Write your question here (Keep it simple and clear to get the best answer) a car accelerates uniformly from an initial velocity
1 answer:
Answer:
Average velocity = 18 m/s
Explanation:
Given the following data;
Initial velocity = 10m/s
Acceleration = 2m/s²
Time = 4 seconds
To find the average velocity, we would use the first equation of motion;
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
V = u + at
V = 10 + 2*4
V = 10 + 8
V = 18 m/s
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Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants ( = 0) zero, so let's use the equation
y = t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch