Write your question here (Keep it simple and clear to get the best answer) a car accelerates uniformly from an initial velocity
1 answer:
Answer:
Average velocity = 18 m/s
Explanation:
Given the following data;
Initial velocity = 10m/s
Acceleration = 2m/s²
Time = 4 seconds
To find the average velocity, we would use the first equation of motion;
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
V = u + at
V = 10 + 2*4
V = 10 + 8
V = 18 m/s
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Refer to the diagram shown below.
In this analysis, wind resistance is ignored, and g = 9.8 m/s².
The meat falls with zero vertical velocity, therefore the time, t, before the meat hits the ground is
If the fox catches the meat before it hits the ground, then the fox should travel a horizontal distance d in the same time that the meat travels a horizontal distance (7 -d).
The meat travels a distance of
7 - d = (1.2 m/s)*(1.75 s) = 2.1 m
or
d = 4.9 m
Let v = velocity of the fox when it catches the meat.
If the acceleration of the fox is a m/s², then
v = 1.75a
Also,
Answer: 2.37 m/s (nearest hundredth)
In this analysis, wind resistance is ignored, and g = 9.8 m/s².
The meat falls with zero vertical velocity, therefore the time, t, before the meat hits the ground is
If the fox catches the meat before it hits the ground, then the fox should travel a horizontal distance d in the same time that the meat travels a horizontal distance (7 -d).
The meat travels a distance of
7 - d = (1.2 m/s)*(1.75 s) = 2.1 m
or
d = 4.9 m
Let v = velocity of the fox when it catches the meat.
If the acceleration of the fox is a m/s², then
v = 1.75a
Also,
Answer: 2.37 m/s (nearest hundredth)