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mylen [45]
3 years ago
7

Write your question here (Keep it simple and clear to get the best answer) a car accelerates uniformly from an initial velocity

of 10m/s at 2m/s squre for 4s.What is the average velocity
Physics
1 answer:
Fittoniya [83]3 years ago
8 0

Answer:

Average velocity = 18 m/s

Explanation:

Given the following data;

Initial velocity = 10m/s

Acceleration = 2m/s²

Time = 4 seconds

To find the average velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

V = u + at

V = 10 + 2*4

V = 10 + 8

V = 18 m/s

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If 190 grams of water is cooled from 42.7°C to 21.2° C how much energy was lost by the water?
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Answer:

Energy lost by the water is 17.1 x 10³ J .

Explanation:

Specific heat is defined as the amount of energy per unit mass needed to raise the temperature of the substance by a one degree Celsius.

Heat energy gain or loss by any substance is given by :

Q = m x C x ( T₁ - T₂ )     .....(1)

Here m is the mass of the substance, C is specific heat of the substance and T₁ and T₂ are the initial and final temperature of the substance.

According to the problem,

Mass of water, m = 190 gm

Specific heat of water, C = 4.186 J gm⁻¹ ⁰C⁻¹

Initial temperature, T₁ = 42.7⁰ C

Final temperature, T₂ = 21.2⁰ C  

Substitute these values in equation (1).

Heat energy loss by water = 190 x 4.186 x ( 21.2 - 42.7 )

                                            =  -17.1 x 10³ J

In the above value, negative sign denotes the loss in energy.

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4 years ago
Carbonic acid _____.
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A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a di
nirvana33 [79]

Answer:

The acceleration towards the center will be 0.43\ m/s^2

Explanation:

Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.

Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.

We need to find the acceleration towards the center.

First, we will find the speed.

v=\frac{d}{t}

Where v is the speed.

d is the distance covered by the rider that is 400 meters.

t is the time taken by the rider to complete the lap which is 1 minute and 40 seconds.  (60\ s +40\ s) = 100 seconds.

So,

v=\frac{400}{100}=4\ m/s

And

a_c=\frac{v^2}{r}

Where a_c is the acceleration towards the center.

r is the radius which will be the half of the diameter 74 meters.

Hence, the radius will be 37 meters.

a_c=\frac{4^2}{37} \\a_c=\frac{16}{37}=0.43\ m/s^2

So, the centripetal acceleration of the rider will be 0.43\ m/s^2

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A boy drops his toy jet out of the window of his apartment. How high is his window if it hit the ground 4.0 seconds later? (for
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