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3 years ago

Drawing a ray diagram for an object far from convex lens requires how many rays?

Physics

1 answer:

Crank3 years ago

5 0

Answer

Explanation:

four rays can also explain the ray diagram if the object is at infinity

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What are the comparisons and contrast of adaptation and natural selection? ASAP!!!!!!

Andre45 [30]

Answer:

Natural selection is a mechanism, or cause, of evolution.

Explanation:

Adaptations are physical or behavioral traits that make an organism better suited to its environment. Heritable variation comes from random mutations.

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3 years ago

Calculate the energy needed to change 200.0 g of ice from -20.0°C to water at 35.0°C.

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3 years ago

If a microwave oven produces electromagnetic waves with a frequency of 2.30 ghz, what is their wavelength?

vovikov84 [41]

Answer: wavelength is $1.30 \times 10^8 nm.$

The frequency of the microwave is, f = 2.30 GHz.

To Find frequency use the formula:

$c=f$ λ

Where, c is the speed of electromagnetic wave or light. f is the frequency, and λ is the wavelength of light.

Rearranging, $\lambda = \frac{c}{f}$

Plug in the values,

$\lambdam = \frac{3 \times 10^8 m/s}{2.30 GHz\frac{10^9 Hz}{1 GHz}}=0.130 m\frac{10^9 nm}{1 m} = 1.30 \times 10^8 nm.$

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4 years ago

Read 2 more answers

A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in

koban [17]

Answer:

a) The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) The electric force is $2.0\times 10^{-6}$ newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

$E = \frac{F_{e}}{q}$ (1)

Where:

$E$ - Electric field, measured in newtons per coulomb.

$F_{e}$ - Electric force, measured in newtons.

$q$ - Electric charge, measured in coulombs.

If we know that $F_{e} = 4.0\times 10^{-6}\,N$ and $q = 2.0\times 10^{-8}\,C$ , then the electric field at that point is:

$E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}$

$E = 2.0\times 10^{2}\,\frac{N}{C}$

The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) If we know that $E = 2.0\times 10^{2}\,\frac{N}{C}$ and $q = 1.0\times 10^{-8}\,C$ , then the electric force is:

$F_{e} = E\cdot q$

$F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)$

$F_{e} = 2.0\times 10^{-6}\,N$

The electric force is $2.0\times 10^{-6}$ newtons.

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3 years ago

What causes diffferent air density?

ololo11 [35]

Answer:

The temperature and gravity both affects the density

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3 years ago