Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is 1.3 atm.
From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;
PT = PA + PB + PC + --------
Given that;
Vapor pressure of oxygen = 0.2 atm
Total pressure = 1.5 atm
Vapor pressure of oxygen = ?
Partial pressure of oxygen = 1.5 atm - 0.2 atm = 1.3 atm
The vapor pressure of oxygen is 1.3 atm.
Learn more: brainly.com/question/2510654
We are given
V = 100 V
R = 500 Ω
C = 10^4 F
q(0) = 0
We are asked to find the charge q(t) of the RC capacitor.
To solve this, we use the formula:
q(t) = CV [1 - e^(-t/RC) ]
Substituting thet given values
q(t) = 10^4 (100) [1 - e^(-t/500(10^4) ]
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Since we only asked to get the charge q(t) in terms of t, the answer is
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Answer:
x=2.4t+4.9t^2
Explanation:
This equation is one of the kinematic equations to solve for distance. The original equation is as follows:
X=Xo+Vt+1/2at^2
We know that the ball starts at rest meaning that its initial velocity and position is zero.
X=0+Vt+1/2at^2
Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.
X=Vt+4.9t^2
Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.
Now, substitute in your velocity value.
X=2.4t+4.9t^2
In 1920, after returning from Army service, he produced a successful model and in 1923 turned it over to the Northeast Electric Company of Rochester for development.