At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball 's acceleration is 890 m/s2 and the vertical or y component of its acceleration is 1100 m/s2. The ball's mass is 0.41 kg. What is the magnitude of the net force acting on the soccer ball at this instant
1 answer:
Answer:
580.13N
Explanation:
The magnitude of the net force is expressed using the expression
F = ma
m is the mass
a is the net acceleration
Given
Mass = 0.41kg
Get the net acceleration
a = √(ax)²+(ay)²
a = √890²+1100²
a = √792100+1210000
a = √2002100
a = 1414.96m/s²
Get the required net force acting on the ball
F = ma
F = 0.41×1414.96
F = 580.13N
Hence the net force acting on the soccer ball at this instant is 580.13N
You might be interested in
<h2>
Magnitude of force doubles. </h2>
Explanation:
Force between two charges is given by
where q₁ and q₂ are charges and r is the distance between them.
Here one charge is doubled with keeping all others same.
q₁ = 2 q₁
We have
Magnitude of force doubles.
B. The meteor accelerates
The answer is Carbonic acid
Answer:
a] 3000hz
b]3.33 × 10⁻⁴
ci]300
ii] 3000
iii]60,000
Explanation:
Answer:
1.122 m/s
Explanation:
So usually a river with a speed of 1 meters per second can transport particle that weighs:
If the particle is twice as massive as usual, then its weights would be 1 * 2 = 2kg
This means the river must be flowing at a speed of
