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olasank [31]
3 years ago
14

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

's acceleration is 890 m/s2 and the vertical or y component of its acceleration is 1100 m/s2. The ball's mass is 0.41 kg. What is the magnitude of the net force acting on the soccer ball at this instant
Physics
1 answer:
mixas84 [53]3 years ago
4 0

Answer:

580.13N

Explanation:

The magnitude of the net force is expressed using the expression

F = ma

m is the mass

a is the net acceleration

Given

Mass = 0.41kg

Get the net acceleration

a = √(ax)²+(ay)²

a = √890²+1100²

a = √792100+1210000

a = √2002100

a = 1414.96m/s²

Get the required net force acting on the ball

F = ma

F = 0.41×1414.96

F = 580.13N

Hence the net force acting on the soccer ball at this instant is 580.13N

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A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
il63 [147K]

Answer:

\huge\boxed{\sf P.E. = 39.2\ Joules}

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
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irinina [24]

Answer:

35 kg

Explanation:

From the question,

Momentum (I) = mass (m) × velocity (v)

I = m×v................... Equation 1

Where m = mass, v = velocity

make m the subject of the equation

m = I/v.................... Equation 2

Given: I = 140 kgm/s, v = 4 m/s

Substitute these values into equation 2

m = 140/4

m = 35 kg

Hence the mass of the dart is 35 kg

6 0
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Answer:

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{}                                    Metal A

Least reactive {}           Metal C

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{}                               Metal A

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The other of reactivity is based on the nature of their reactivity of the metals in air

(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly

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hodyreva [135]

Answer:

A- mass and type of material

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