This is the concept of algebra; given that the height of the house at time t is given by:
h(t)=<span> 400 − 39t − 157e−t/4
the velocity of the house is given by:
dh/dt
velocity of our object is:
dh/dt=-39+1/4*157e^-(t/4)
=-39+157/4 e^(-t/4)
thus the velocity at h=0 will be as follows:
at h=0, the value of t will be:
0=400-39t-157e^(-t/4)
solving for t we get:
t=-5.4 or t=10.1
since we don't have negative time, t=10.1
thus the velocity at this point will be:
dh/dt=-38+1/4*157e^(-10.1/4)
=-38.86 sec
this means that the object dropped by a velocity of 38.86 sec</span>
The answer is 1/14. -3/7 x -1/6. 3 crosses 6 2 time so you are left with -1/7 x -1/2 that is 1/14
Answer:
Bottom left graph.
Step-by-step explanation:
I answered this by finding the y-int.
8(0) - 3y = 18
-3y = 18
y = -6
And it has a positive relationship so the line slants from bottom left to top right.
Answer:
The answer to your question is h = 125.85 ft = 126 ft
Step-by-step explanation:
Process
1.- Determine two equations to solve the problem
(1)
(2)
from (1) h = xtan14
substitute in (2) tan 47 = 
solve for x tan47(x - 386) = xtan14
1.07x - 413.9 = 0.25x
1.07x - 0.25x = 413.9
0.82x = 413.9
x = 413.9/0.82
x = 504.76 ft
2.- Calculate h
h = 504.76 tan 14
h = 125.85 ft = 126 ft
