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Juliette [100K]
3 years ago
14

Which multiplication has a negative answer?

Mathematics
2 answers:
ki77a [65]3 years ago
6 0
C has a negative answer. hope this helps
Katen [24]3 years ago
6 0
I think the answer is C.
You might be interested in
Find two consecutive intergers whose sum is -29
boyakko [2]
-29= x + (x + 1)
-29= 2x +1
-30= 2x
-15=x
The answer is -15, -14.
6 0
3 years ago
Solve the system of equations 2x-2y=-14 and 3x-y=-1 by combining the equations.
Veseljchak [2.6K]

The solution to the system of equations is x = 3 and y = 10

<h3>How to solve the equations?</h3>

The system is given as:

2x-2y=-14

3x-y=-1

Multiply (1) by 1 and (2) by 2

So, we have:

1(2x-2y=-14)

2(3x-y=-1 )

This gives

2x - 2y=-14

6x - 2y=-2

Subtract the equations

-4x = -12

Divide by -4

x = 3

Substitute x = 3 in 3x-y=-1

3(3)-y=-1

Evaluate

9 - y = -1

Solve for y

y = 10

Hence, the solution to the system of equations is x = 3 and y = 10

Read more about system of equations at:

brainly.com/question/12895249

#SPJ1

7 0
2 years ago
Please help me someone
Aneli [31]
There is a formula for the area of a parallelogram which is bxh
(base x height)

Remember the height is always straight so do not use the 12 value.

21x9=189

Hope this helped!

7 0
3 years ago
If y varies directly as the square root of x and y = 8 when x = 36, find the value of y when x = 144. y =
Wittaler [7]

Answer:

y=32

Step-by-step explanation:

cross multiply

36/4 *144/y

144*8/36

=1152/36

y=32

8 0
3 years ago
If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?
Diano4ka-milaya [45]

Answer:

x=8

\m\angle HFG= 80^\circ

Step-by-step explanation:

Given that:

Point H is interior of \angle EFG.

m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ

To find:

x = ?\\m\angle HFG = ?

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

m\angle EFG = m\angle EFH + m\angle HFG

Putting all the values given in above equation, we get:

(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}

m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}

8 0
3 years ago
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