Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
![10log\frac{I (W/m^2)}{I_o} = I (dB)\\\\10log\frac{I }{1*10^{-12}} = 2.6\\\\log(\frac{I }{1*10^{-12}})^{10} = 2.6\\\\10^{2.6} = (\frac{I }{1*10^{-12}})^{10} \\\\10^{\frac{2.6}{10}} = \frac{I }{1*10^{-12}}\\\\1.8197 = \frac{I }{1*10^{-12}}\\\\I = 1.8197 *1*10^{-12} = 1.8197 *10^{-12} \ W/m^2](https://tex.z-dn.net/?f=10log%5Cfrac%7BI%20%28W%2Fm%5E2%29%7D%7BI_o%7D%20%3D%20I%20%28dB%29%5C%5C%5C%5C10log%5Cfrac%7BI%20%7D%7B1%2A10%5E%7B-12%7D%7D%20%3D%202.6%5C%5C%5C%5Clog%28%5Cfrac%7BI%20%7D%7B1%2A10%5E%7B-12%7D%7D%29%5E%7B10%7D%20%3D%202.6%5C%5C%5C%5C10%5E%7B2.6%7D%20%3D%20%28%5Cfrac%7BI%20%7D%7B1%2A10%5E%7B-12%7D%7D%29%5E%7B10%7D%20%5C%5C%5C%5C10%5E%7B%5Cfrac%7B2.6%7D%7B10%7D%7D%20%3D%20%5Cfrac%7BI%20%7D%7B1%2A10%5E%7B-12%7D%7D%5C%5C%5C%5C1.8197%20%3D%20%5Cfrac%7BI%20%7D%7B1%2A10%5E%7B-12%7D%7D%5C%5C%5C%5CI%20%3D%201.8197%20%2A1%2A10%5E%7B-12%7D%20%3D%201.8197%20%2A10%5E%7B-12%7D%20%5C%20W%2Fm%5E2)
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²
Well the shown circuit is definitely open because the lines are not connected. And it is not a parallel circuit because there would be more lines. Like a string of Christmas lights. So it must be an "open series circuit".
Answer:
I think it's the last one
Explanation:
good luck
Acceleration = r w² radius r = 0.82 meter angular velocity w
4.7 = 0.82 w²
So w = 2.394 radians / sec
Time period T = time duration for completing one revolution = 2 π / w
= 2π / 2.394 = 2.624 seconds
To hit the target the crew drop the crate before the plane is directly over the target. It is because <span>because the cargo has forward velocity and therefore before it reaches the ground it travels some distance. The answer is A. Hope it helps. </span>