The kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
<h3>What is threshold frequency?</h3>The threshold frequency of incoming radiation is the lowest frequency at which photoelectric emission or electron emission is impossible.
The threshold frequency is the light frequency that causes an electron to dislodge and emit from the metal's surface.
From the photoelectric effect, the equation obtained as;
Hence,the kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
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Answer:
The intensity of the light that passes through a polarizer is 0.55I₀.
Explanation:
The intensity of the light that passes through a polarizer can be found using Malus's law:
<u>Where</u>:
I: is the intensity of the light that passes through a polarizer
I₀: is the initial intensity
θ: is the angle between the light's initial polarization direction and the axis of the polarizer = 42°
Therefore, the intensity of the light that passes through a polarizer is 0.55I₀.
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Answer:
117.83° F
Explanation:
Using Newton's Law of Cooling which can be expressed as:
The differential equation can be computed as:
where;
At the initial condition, T(0)= 350
replacing = 280 into (1)
Hence, the differential equation becomes:
when;
time (t) = 1 hour
T(1) = 250
Since;
k = -0.4418
Therefore;
T(t) = 70 + 280e^{(-0.4418)}t
After 4 hours, the temperature is:
T(t) = 70 + 280e^{(-0.4418)}4
T(4) = 117.83° F