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3 years ago

What causes the formation of mountain ranges along the ocean floor?

2 answers:

4 0

I think it is plate tectonics pulls the ocean floor apart and magma pushes up forming mountains, please tell me if i’m wrong but i hope this helps

Rainbow [258]3 years ago

3 0

It’s the second answer

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Which of the following describe chemical properties?

KengaRu [80]

Sugar burns in air.....................................

6 0

3 years ago

What is the nuclear charge of a berrylium atom?

ICE Princess25 [194]

Answer:

The charge on the nucleus of an atom; controlled by the number of protons and electrons present in an atom.

Explanation:

4 0

3 years ago

In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is

V125BC [204]

Answer:

the Molar heat of Combustion of diphenylacetylene $(C_{14}H_{10})$ = $-6.931 *10^3 \ kJ/mol$

Explanation:

Given that:

mass of diphenylacetylene $(C_{14}H_{10})$ = 0.5297 g

Molar Mass of diphenylacetylene $(C_{14}H_{10})$ = 178.21 g/mol

Then number of moles of diphenylacetylene $(C_{14}H_{10})$ = $\frac{mass}{molar \ mass}$

= $\frac{0.5297 \ g }{178.24 \ g/mol}$

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = Heat absorbed by $H_2O$ + Heat absorbed by the calorimeter

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = msΔT + cΔT

= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = 20598.87 J

Heat liberated by 1 mole of diphenylacetylene $(C_{14}H_{10})$ will be = $\frac{20598.87 \ J}{0.002972 \ mol}$

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene $(C_{14}H_{10})$ = $-6.931 *10^3 \ kJ/mol$

3 0

3 years ago

Read 2 more answers

Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip

avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

q = $600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}$

= 0.0378 $m^{3}/s
$

Diameter = $8 in \times \frac{0.0254 m}{1 in}$

= 0.2032 m

Relation between area and diameter is as follows.

A = $\frac{\pi}{4} \times D^{2}$

= $\frac{3.14}{4} \times (0.2032 m)^{2}$

= 0.785 x 0.2032 x 0.2032

= 0.0324 $m^{2}$

Also, q = A × V

or, V = $\frac{q}{A}$

= $\frac{0.0378 m^{3}/s}{0.0324 m^{2}}$

= 1.166 m/s

As, viscosity of water = 1 cP = $10^{-3}$ Pa-s

Density of water = 1000 $kg/m^{3}$

Therefore, we will calculate Reynolds number as follows.

Reynolds number = $\frac{D \times V \times density}{viscosity}$

= $\frac{0.2032 m \times 1.166 m/s \times 1000}{10^{-3}}$

= 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0

3 years ago

What is the molarity (M) of chloride ions in a solution prepared by mixing 155 ml of 0.276 M calcium chloride with 384 ml of 0.4

sesenic [268]

Answer: The concentration of $Cl^-$ ions in the resulting solution is 1.16 M.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the $CaCl_2$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $AlCl_3$

We are given:

$n_1=2\\M_1=0.276M\\V_1=155mL\\n_2=3\\M_2=0.471M\\V_2=384mL$

Putting all the values in above equation, we get

$M=\frac{(2\times 0.276\times 155)+(3\times 0.471\times 384)}{155+384}\\\\M=1.16M$

The concentration of $Cl^-$ ions in the resulting solution will be same as the molarity of solution which is 1.16 M.

Hence, the concentration of $Cl^-$ ions in the resulting solution is 1.16 M.

6 0

3 years ago