of oxygen at STP would be required to react completely with 38.8g of propane.
<u>Given that :</u>
molar mass of propane = 44 g/mol
mass of propane = 38.8 g
∴ Moles present in 38.8 g of propane =
= 0.88 mole
<u>applying rule of balanced equations </u>
1 mole of propane = 5 moles of oxygen
0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen
Note : volume of 1 mole of oxygen at STP = 
∴Total volume of oxygen required at STP = 22.4 * 4.4 = 
Hence we can conclude that the volume of oxygen at STP required to react completely 
Learn more : brainly.com/question/16998374
Answer:
1 electron
Explanation:
These metals have a single electron in the outer shell
I have attached a paper with the answer. hope you understand. let me know if you have any question
2.0 L in mL :
2.0 x 1000 => 2000 mL
1.26 kg in g :
1.26 x 1000 => 1260 g
D = mass / volume
D = 1260 / 2000
D = 0.63 g/mL
hope this helps!