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o-na [289]
3 years ago
6

A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is chan

ged to 1880 mL and the pressure is changed to 38.7 kPa?
(1) 31.5 K (3) 566 K(2) 292 K (4) 2360 K
Chemistry
2 answers:
kifflom [539]3 years ago
7 0

Answer:

566K

Explanation:

sergij07 [2.7K]3 years ago
6 0
The answer is (3) 566 K. For this problem, you need the combined gas law, which is P1V1/T1 = P2V2/T2 (variables represent Pressure, Volume, and Temperature). You are looking for T2, so you get T2 = P2V2T1/P1V1 = (38.7)(1880)(273)/(79.0)(444) = 566 K.
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Answer:

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Explanation:

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7 0
3 years ago
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Answer:

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Explanation:

The reaction expression is given as:

          Li   +   F₂    →     LiF

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 Let use a mathematical approach to solve this problem;

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Conserving Li: a  = c

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5 0
3 years ago
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Answer:

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