Answer:
Explanation:
What we need to do here is to determine the ratios by using the Rydberg equation starting with the transition to n1 = 1, 2,3, etc and see which one fits the data. Remember the question states that they are series and the wavelengths will be for increasing energy levels.
1/λ = Rh x ( 1/n₁² - 1/n₂²)
Lyman series ( n₁=1 and n₂= 2,3 etc) for the first two lines, the ratios will be:
1/λ₁ /1/λ₂ =(1/1 -1/ 2²) / (1/1 -1/ 3²) ⇒ 0.84 ≠ 0.74 (the first ratio)
For Balmer series n₁ = 2 and n₂ = 3,4,5, etc
1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/4²) ⇒ 0.741 = 0.741 (match!)
Lets use the third line to check our answer:
1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/5²) = 0.66
Answer:
d = 0.992 g/L
Explanation:
Data Given:
Pressure of nitric oxide (NO) = 0.866 atm
Temperature of a gas = 46.2° C
Convert the temperature to kelvin = 46.2° C + 273
temperature in kelvin = 319.2 K
density of nitric oxide (NO) = ?
Solution:
Density of a gas can be calculated by
d = PM /RT
Where
d = density
P = Pressure
M = molar mass of gas
R = ideal gas constant = 0.0821 L atm mol⁻¹ K⁻¹
T = temperature
So,
Molar mass of NO = 30 g/mol
Put values in the formula:
d = PM /RT
d = 0.866 atm × 30 g/mol / 0.0821 L atm mol⁻¹ K⁻¹ × 319.2 K
d = 25.98 atm. g/mol / 26.2 L atm mol⁻¹
d = 0.992 g/L
Answer:
A weak acid
Explanation:
Im not sure if its right. But lets see someone else do it.
Answer:
No
Explanation:
loss of electron doesn't affect the element.
only change in proton number can, as we notice in nuclear chemistry.
please mark brainliest
Answer: C. the warmer object transfers heat energy to the cooler side
