Given the formula for a compound:

Chemistry

1 answer:

Elina [12.6K]2 years ago

8 0

Answer:

Explanation:

4 carbon equals butane

O=C-NH2 equals amide

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Why are naturally occurring substances, such as particulates or carbon dioxide, sometimes considered pollutants?

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Because despite being natural they still harm the ozone layer and cause breathing problems, even suffocation.

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Drag each characteristic to the correct category.

andrew11 [14]

Answer/Explanation

Characteristics of Life Present in Viruses:

has a defined boundary - viruses are made up simply of genetic material surrounded by a protein capsid and sometimes a lipid membrane

Characteristics of Life Absent in Viruses:

made up of one or more cells - one of the main arguments for why viruses are not living is that they are not cellular
uses energy - this is a tricky one. They don't use or produce their own energy. However, in order to reproduce they do hijack the host cells and steal energy from them in order to reproduce
exhibits growth and development - although viruses do reproduce, the individual viral particles do not exhibit growth or development
possess internal organisation - other than the fact they ahve genetic material, the inside of a virus does not contain internal organization like a cytosol, instead conssiting of the bare minimum amount of proteins to survive
eliminates waste - since they do not have their own metabolism, they have no waste to eliminate

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2 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$