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Lostsunrise [7]
3 years ago
10

Observe: Click Reset. Turn on Show velocity vector and Show velocity components. Set vinitial to 50 m/s and set θ to 45.0 degree

s. Click Play. Focus on the blue and red arrows that represent the vertical and horizontal components of the golf ball’s velocity. As the ball flies through the air, what do you notice about the blue (vertical) arrow?
Physics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

Explanation:

In this exercise you are asked to observe the change in velocity in a projectile launch.

If we assume that the friction force is small, the velocity in the x-axis must be constant

         vₓ = v₀ₓ

Therefore, the arrow (red) that represents this movement must not change in magnitude.

In the direction of the y axis, the acceleration of gravity is acting, so the magnitude of the velocity in this axis changes

         v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

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Give an example of a theory scientists believed for a long time that was eventually proved false
jolli1 [7]
There are so many to choose from, I'll give you two. One is a big one. The other so/so. People used to believe the earth was flat and you would fall off, until Christopher Columbus sailed across. And another interesting one is the vulcan planet theory, which is that there was an extra planet between Mercury and T sun. however it turned out to be false. So there, need anymore just tell me.
6 0
3 years ago
The phase of matter which is exposed to normal atmospheric pressure is solely dependent upon temperature? true or false
Diano4ka-milaya [45]
The statement above is true. The phase of matter which is exposed to normal atmospheric pressure is indeed solely dependent upon temperature. If the matter is exposed to the normal atm pressure, its temperature depends on it.
6 0
3 years ago
What is the energy difference between parallel and antiparallel alignment of the z component of an electron's spin magnetic dipo
Readme [11.4K]

Answer:

\Delta U= 4.8204\times10^{-24} J

Explanation:

The difference between parallel and anti parallel alignment of the z component of an electron's spin magnetic dipole moment  is given by

U_1-U_2= (-\mu Bcos(\theta_2))-(-\mu Bcos(\theta_1))

where  μ= dipole moment B= strength of magnetic field and θ= angle between direction of magnetic field and dipole

here θ_2 and θ_1 are 180 and 0° respectively.

U_1-U_2= (\mu B)-(-\mu B)

U_1-U_2= 2\mu B

here μ is bohr magnetron or  magnetic moment of an electron = 9.27×10^{-24}

put this value we get

U_1-U_2= 2\times 9.27\times10^{-24}(0.26)

\Delta U= 4.8204\times10^{-24} J

3 0
3 years ago
A fuzzy bunny sees a butterfly and chases it right off of a 20 m high cliff at 7m/s
bogdanovich [222]

A) 2.02 s

To find the time it takes for the bunny to reach the rocks below the cliff, we just need to analyze its vertical motion. This motion is a free fall motion, which is a uniformly accelerated motion. So we can use the suvat equation:

s=u_y t+\frac{1}{2}at^2

where

s is the vertical displacement

u is the initial vertical velocity

a is the acceleration

t is the time

For the bunny here, choosing downward as positive direction,

u_y = 0 (initial vertical velocity is zero)

s = 20 m

a=g=9.8 m/s^2 (acceleration of gravity)

And solving for t, we find the time of flight:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

B) 14.1 m

For this part, we need to consider the horizontal motion of the bunny.

The horizontal motion of the bunny is a uniform motion with constant velocity, which is the initial velocity of the bunny:

v_x = 7 m/s

Therefore the distance covered after time t is given by

d=v_x t

And substituting the time at which the bunny hits the ground,

t = 2.02 s

We find how far the bunny went from the cliff:

d=(7)(2.02)=14.1 m

C) 21.0 m/s at 70.5^{\circ} below the horizontal

The horizontal component of the velocity is constant during the entire motion, so it will still be the same when the bunny hits the ground:

v_x = 7 m/s

Instead, the vertical velocity is given by

v_y = u_y +at

And substituting t = 2.02 s, we find the vertical velocity at the moment of impact:

v_y = 0+(9.8)(2.02)=19.8 m/s

So, the magnitude of the final velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{7^2+(19.8)^2}=21.0 m/s

And the angle is given by

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{19.8}{7})=70.5^{\circ}

below the horizontal

5 0
3 years ago
The process of loosening of soil is called ?
IrinaK [193]
Answer is : a) tilling
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