Answer:
ΔP = (640 N/cm^2)
Explanation:
Given:-
- The volume increase, ΔV/V0 = 4 ✕ 10^-3
- The Bulk Modulus, B = 1.6*10^9 N/m^2
Find:-
Calculate the force exerted by the moonshine per square centimeter
Solution:-
- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.
B = ΔP / [(ΔV/V)]
- Now rearrange the above relation and solve for ΔP or force per unit area.
ΔP = B* [(ΔV/V)]
- Plug in the values:
ΔP = (1.6*10^9)*(4 ✕ 10^-3)
ΔP = 6400000 N/m^2
- For unit conversion from N/m^2 to N/cm^2 we have:
ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2
ΔP = (640 N/cm^2)
Answer:
C. The distance traveled by an object at a certain velocity.
Explanation:
YW!
Answer:
v = 8.09 m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
starting point. Higher
Em₀ = U = m gh
final point. To go down the slope
Em_f = K = ½ m v²
The work of the friction force is
W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
N - W_y = 0
N = W_y
X axis
Wₓ - fr = ma
let's use trigonometry
sin θ = y / L
sin θ = 11/110 = 0.1
θ = sin⁻¹ 0.1
θ = 5.74º
sin 5.74 = Wₓ / W
cos 5.74 = W_y / W
Wₓ = W sin 5.74
W_y = W cos 5.74
the formula for the friction force is
fr = μ N
fr = μ W cos θ
Work is friction force is
W_fr = - μ W L cos θ
Let's use the relationship of work with energy
W + ΔU = ΔK
-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²
v² = - 2 μ g L cos 5.74 +2 (gh)
v² = 2gh - 2 μ gL cos 5.74
let's calculate
v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
v² = 215.6 -150.16
v = √65.44
v = 8.09 m/s
The correct answer for the question that is being presented above is this one: "(a)4." Suppose that during any period of 1/4 second there is one instant at which the crests or troughs of component waves are exactly in phase and maximum <span>reinforcement occurs, in 1 second, there will be 4 beats.</span>
Answer:
The tension is 75.22 Newtons
Explanation:
The velocity of a wave on a rope is:
(1)
With T the tension, L the length of the string and M its mass.
Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:
(2)
We can equate expression (1) and (2):
=
Solving for T
(3)
For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic is:
It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:
We can now find T on (3) using all the values we have: