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dexar [7]
3 years ago
14

Define Momentum in detail.

Physics
2 answers:
Harrizon [31]3 years ago
8 0

Explanation:

Momentum Is defined as the product of of mass and its velocity

Momentum (M) =mass *velocity

SI unit of momentum is kgm/s

The rate of change in momentum

=change in momentum / time

=(mv-mu)/t

blsea [12.9K]3 years ago
7 0

Answer:

Momentum is simply the product of mass and velocity. It is represented mathematically as

Momentum = Mass x Velocity.

The S. I unit of momentum is kilograms meter per second i.e Kg.m/s.

Momentum is a vector quantity i.e it has both magnitude and direction.

Momentum of an object is greatly affected my the mass and velocity of the object as we can clear from the equation.

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The coal with the highest energy available per unit burned is:________
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you ride a bike for 2 hours at 25 km/hr then 3 hours at 34 km/hr. what is your average velocity (in km/hr)?
mamaluj [8]
<h3>Answer:</h3>

30.4 km/hr

<h3>Explanation:</h3>

<u>We are given</u>;

  • Speed in the first 2 hours as 25 km/hr
  • Speed in the next 3 hours as 34 km/hr

We are required to determine the average velocity in km/hr

  • To get the average velocity we divide total distance by total time.
  • Thus, we need to determine the total distance

Distance = Speed × time

Distance covered in the first 2 hours;

               = 25 km/hr × 2 hours

               = 50 km

Distance in the next 3 hours

                = 34 km/hr × 3 hours

                = 102 km

Therefore, total distance = 50 km + 102 km

                                        = 152 km

Total time = 2 hrs + 3 hrs

                = 5 hours

Therefore;

Average speed = 152 km ÷ 5 hours

                          = 30.4 km/hr

Thus, the average speed is 30.4 km/hr

4 0
3 years ago
A thin rod (length = 1.09 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
Murljashka [212]

Answer:

a) w = 4.24 rad / s , b) α  = 8.99 rad / s²

Explanation:

a) For this exercise we use the conservation of kinetic energy,

Initial. Vertical bar

        Emo = U = m g h

Final. Just before touching the floor

       Emf = K = ½ I w2

As there is no friction the mechanical energy is conserved

       Emo = emf

       mgh = ½ m w²

The moment of inertial of a point mass is

        I = m L²

       m g h = ½ (m L²) w²

       w = √ 2gh / L²

The initial height h when the bar is vertical is equal to the length of the bar

         h = L

         w = √ 2g / L

Let's calculate

       w = RA (2 9.8 / 1.09)

       w = 4.24 rad / s

b) Let's use Newton's equation for rotational motion

         τ = I α

         F L = (m L²) α

The force applied is the weight of the object, which is at a distance L from the point of gro

         mg L = m L² α  

          α  = g / L

          α  = 9.8 / 1.09

          α  = 8.99 rad / s²

5 0
3 years ago
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