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3 years ago

Define Momentum in detail.

Physics

2 answers:

Harrizon [31]3 years ago

8 0

Explanation:

Momentum Is defined as the product of of mass and its velocity

Momentum (M) =mass *velocity

SI unit of momentum is kgm/s

The rate of change in momentum

=change in momentum / time

=(mv-mu)/t

blsea [12.9K]3 years ago

7 0

Answer:

Momentum is simply the product of mass and velocity. It is represented mathematically as

Momentum = Mass x Velocity.

The S. I unit of momentum is kilograms meter per second i.e Kg.m/s.

Momentum is a vector quantity i.e it has both magnitude and direction.

Momentum of an object is greatly affected my the mass and velocity of the object as we can clear from the equation.

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When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries?

Ket [755]

Answer:

Explanation:

Assume that a single baby cries at X db

4 babies crying would be X + 10log₁₀(4) = X + 6 db

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2 years ago

Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha

Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

$n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}$

It means she can send 52 oranges and it is maximum quantity.

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3 years ago

A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction

mezya [45]

A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction between the box and the surface of the incline is 0.180. the initial speed of the box at the bottom of the incline is 2.20 m/s. how far does the box travel along the incline before coming to rest?

6 0

3 years ago

A 0.900-V potential difference is maintained across a 1.5m length of 2

Daniel [21]

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, $A=0.6\ mm^2=6\times 10^{-7}\ m^2$