Hello!
The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.
We have the following data:
mo (initial mass) = 20 g
m (final mass after time T) = 5 g
x (number of periods elapsed) = ?
P (Half-life) = ? (in minutes)
T (Elapsed time for sample reduction) = 8 minutes
Let's find the number of periods elapsed (x), let us see:
![m = \dfrac{m_o}{2^x}](https://tex.z-dn.net/?f=%20m%20%3D%20%20%5Cdfrac%7Bm_o%7D%7B2%5Ex%7D%20)
![5 = \dfrac{20}{2^x}](https://tex.z-dn.net/?f=%205%20%3D%20%20%5Cdfrac%7B20%7D%7B2%5Ex%7D%20)
![2^x = \dfrac{20}{5}](https://tex.z-dn.net/?f=%202%5Ex%20%3D%20%5Cdfrac%7B20%7D%7B5%7D%20%20)
![2^x = 4](https://tex.z-dn.net/?f=%202%5Ex%20%3D%204%20)
![2^x = 2^2](https://tex.z-dn.net/?f=%202%5Ex%20%3D%202%5E2%20)
![\boxed{x = 2}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bx%20%3D%202%7D%20)
Now, let's find the half-life (P) of the radioactive sample, let's see:
![T = x*P](https://tex.z-dn.net/?f=%20T%20%3D%20x%2AP%20)
![8 = 2*P](https://tex.z-dn.net/?f=%208%20%3D%202%2AP%20)
![2\:P = 8](https://tex.z-dn.net/?f=%202%5C%3AP%20%3D%208%20)
![P = \dfrac{8}{2}](https://tex.z-dn.net/?f=%20P%20%3D%20%5Cdfrac%7B8%7D%7B2%7D%20%20)
![\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7BP%20%3D%204%5C%3Aminutes%7D%7D%5CLongleftarrow%28Half-Life%29%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20)
I Hope this helps, greetings ... DexteR! =)
Answer:
57.8kg
Explanation:
Potential energy is given by:
![U =mgh](https://tex.z-dn.net/?f=U%20%3Dmgh)
Where U is potential energy, m is mass, g is acceleration due to gravity, and h is height. Using this equation:
![3400=m(9.8)(6)\\3400=58.8m\\m=57.8kg](https://tex.z-dn.net/?f=3400%3Dm%289.8%29%286%29%5C%5C3400%3D58.8m%5C%5Cm%3D57.8kg)
Answer:
6 moles of SO₃ formed.
Explanation:
Given data:
Number of moles of SO₃ formed = ?
Number of moles of oxygen react = 3 mol
Solution:
Chemical equation;
2SO₂+ O₂ → 2SO₃
now we will compare the moles of oxygen and sulfur trioxide.
O₂ : SO₃
1 : 2
3 : 2/1×3 = 6 moles
Thus, six moles of SO₃ will formed.
Answer:
Density is the ratio of the mass of an object to its volume. Density is an intensive property, meaning that it does not depend on the amount of material present in the sample. ... Since a cubic centimeter is equal to a milliliter, density units can also be expressed as g/mL.
Explanation:
The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.