In spring mass system we know that angular frequency is given as
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
f = 8.38 Hz
![\omega = 2\pi(8.38)](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%288.38%29)
![\omega = 52.65 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%2052.65%20%20rad%2Fs)
now we know that speed of SHM at its extreme position is given by
![v = A\omega](https://tex.z-dn.net/?f=v%20%3D%20A%5Comega)
here we know that
A = 17.5 cm
![v = 0.175 (52.65)](https://tex.z-dn.net/?f=v%20%3D%200.175%20%2852.65%29)
![v = 9.21 m/s](https://tex.z-dn.net/?f=v%20%3D%209.21%20m%2Fs)
so maximum speed is 9.21 m/s
A child climbing a ladder is transforming kinetic energy into potential energy.
Answer:
at 10 seconds.. b/c that's when the velocity stops increasing..
Explanation:
Answer:
The burden distance is 7 ft
Solution:
As per the question:
Specific gravity of package emulsion, ![SG_{E} = 1.25](https://tex.z-dn.net/?f=SG_%7BE%7D%20%3D%201.25)
Specific gravity of diabase rock, ![SG_{R} = 2.76](https://tex.z-dn.net/?f=SG_%7BR%7D%20%3D%202.76)
Diameter of the packaged sticks, d = 3 in
Now,
To calculate the first trail shot burden distance, B:
![B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2SG_%7BE%7D%7D%7BSG_%7BR%7D%7D%20%2B%201.5%5D%5Ctimes%20d)
![B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2%5Ctimes%201.25%7D%7B2.76%7D%20%2B%201.5%5D%5Ctimes%203%20%3D%207.22)
B = 7 ft
Explanation:
not physics tho??? idkkkkkkkkk sorrrryyyyyy