2 years ago

Help pleasessssssssssssss

Physics

1 answer:

irinina [24]2 years ago

5 0

Sorry I had the answer but it wont let me type numbers :(.:

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What is the mass of a person running at 2.5 m/s with momentum of<br> 200 kg m/S

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A 45kg skater and a 60kg skater are standing still, holding hands on frictionless ice. They push away from each other in opposit

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Answer:

The 60 kg skater is traveling at 2.63 m/s in the opposite direction from the 45 kg skater.

Explanation:

The velocity of the 60 kg skater can be found by conservation of linear momentum:

$P_{i} = P_{f}$

$m_{a}v_{i_{a}} + m_{b}v_{i_{b}} = m_{a}v_{f_{a}} + m_{b}v_{f_{b}}$ (1)

Where:

$m_{a}$ : is the mass of the first skater = 45 kg

$m_{b}$ : is the mass of the second skater = 60 kg

$v_{i_{a}}$ : is the initial speed of the first skater = 0 (he is standing still)

$v_{i_{b}}$ : is the initial speed of the second skater = 0 (he is standing still)

$v_{f_{a}}$ : is the final speed of the first skater = 3.5 m/s

$v_{f_{b}}$ : is the final speed of the second skater =?

By replacing the above values into equation (1) and solving for $v_{f_{b}}$ we have:

$0 = m_{a}v_{f_{a}} + m_{b}v_{f_{b}}$

$v_{f_{b}} = \frac{-m_{a}v_{f_{a}}}{m_{b}} = \frac{-45 kg*3.5 m/s}{60 kg} = -2.63 m/s$

The minus sign is because the 60 kg skater is moving in the opposite direction from the other skater.

Therefore, the 60 kg skater is traveling at 2.63 m/s in the opposite direction from the 45 kg skater.

I hope it helps you!

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3 years ago