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Mazyrski [523]
3 years ago
8

Imagine an alternate universe where all of the quantum number rules were identical to ours except m_{s} had three allowed values

(rather than two as it does in our universe). If this were the case, and the Pauli Exclusion Principle still applies, how many electrons would be allowed in each orbital
Physics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

so in a given orbital there can be 3 electrons.

Explanation:

The Pauli exclusion principle states that all the quantum numbers of an electron cannot be equal, if the spatial part of the wave function is the same, the spin part of the wave function determines how many electrons fit in each orbital.

In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.

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What are the four answers (in order) to fill in these blanks?<br><br> URGENT
ser-zykov [4K]

In a circuit, the electromotive force can be said to be the "source" of the "pushed electrons". This push then creates what is known as a current, which is the flow of electric charge through the circuit. This flow can be slowed down or restricted by a resistor, and this is also what can be harnessed in order to use electric power.

Explanation:

The electromotive force is the potential difference produced by the battery in the circuit. When the circuit is connected to the battery, this potential difference causes the electron to start moving towards the point at higher potential: in this sense, the electromotive force is said to be the "source" of the "pushed electrons".

This flow of electrons moving in the circuit is known as current.

Then, in the circuit, it is possible to place a piece of circuit with a smaller cross-section that restricts the flow of electrons: this component is known as resistor, and its property of restricting the flow of electron is known as resistance.

In a circuit, electromotive force (V), current (I) and resistance (R) are related by Ohm's law:

V=RI

Finally, when a current passes through a resistor, part of the electric energy is converted into thermal energy, and some power is dissipated through the resistor. The power dissipated is given by

P=I^2 R

This power can be harnessed, for instance, if the resistor is connected to a light bulb: the energy is transformed into heat and light, and so the light bulb turns on, providing illumination.

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3 0
3 years ago
Calculate the force generated by a car that hits the wall at an
Makovka662 [10]

This is a defective question. It was WRITTEN by someone who is unclear on the concepts.  DON'T try and answer it.

It's trying to get us to use Newton's second law ... F = m • a.

But that only tells us how much force must act ON THE CAR in order to accelerate it. (45 kg) • (4 m/s^2) = 180 newtons.

This is NOT the force exerted BY the car when it hits something. THAT force depends on its speed WHEN it hits, AND how long it takes for the wreckage to actually come to rest, AND how hard or soft the wall is.

DON'T try to answer this question. Your answer will be wrong, you won't understand why, and the teacher you try to argue with probably won't either.

============================================

More explanation:

Think about jumping off of a ladder in your back yard.  Several times.

Your mass is the same every time.  Your acceleration is the same every time . . . 9.8 m/s² down, the acceleration of Earth gravity, every time.

BUT ...

-- I'll bet you would rather land on wood than on concrete. The force of landing would be less.

-- I'll bet you would rather land on dirt than on wood. The force of landing would be less.

-- I'll bet you would rather land on grass than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a pile of blankets than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a trampoline than on a pile of blankets. The force of landing would be less.

-- I'll bet you would rather jump from a short ladder than from a tall one.  Your speed would be less when you landed, and the force of landing would be less.

==> Your mass is the SAME every time, and your acceleration is the SAME every time.  But the force when you hit is DIFFERENT every time.

The mass and acceleration of the car DON'T tell us the force of the hit when the car hits a wall.  

6 0
3 years ago
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