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Stolb23 [73]
2 years ago
12

Which of the following is true for gravitational force?

Physics
2 answers:
Oliga [24]2 years ago
8 0

Answer:

The gravitational force b) Increases with increase in mass.

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}F=Gr2m1m2

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

From the equation, we notice that:

- The force is proportional to the masses, m1 and m2: so, if the masses increase, the force will increase, and if the masses decrease, the force will decrease

- The force is inversely proportional to the distance between the masses, r: so, if the distance increases,  the force will decreases, and if the distance decreases , the force will increases

Therefore, the correct options is only:

Increases with increase in mass

AveGali [126]2 years ago
6 0

Answer: The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have.

Explanation: Which of the following is true for gravitational force?

Group of answer choices

Decreases with decrease in distance

Increases with increase in distance

Decreases with increase in mass

Increases with increase in mass

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Light bulb is connected to a 110-V source. What is the resistance of this bulb if it is a 100-W bulb
masya89 [10]

Answer:

<h2>121ohms</h2>

Explanation:

Formula used for calculating power P = current * voltage

P = IV

From ohms law, V = IR where R is the resistance. Substituting V = IR into the formula for calculating power, we will have;

P = IV

P =(V/R)V

P = V²/R

Given parameters

Power rating of the bulb P = 100 Watts

Source voltage V = 110V

Required

Resistance of the bulb R

Substituting the given parameters into the formula for calculating power to get Resistance R;

P = V²/R

100 = 110²/R

R = 110²/100

R = 110 * 110/100

R = 12100/100

R = 121 ohms

<em>Hence, the resistance of this bulb is 121 ohms</em>

5 0
3 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
A dumbell has a mass of 95 kg. What force must be applied to accelerate it upward at 2.2 m/s2?
Sveta_85 [38]
A :-) F = ma
Given - m = 95 kg
a = 2.2 m/s^2
Solution -
F = ma
F = 95 x 2.2
F = 209

.:. The force is 209 N
5 0
2 years ago
A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w
Scilla [17]

Answer:

v_f = 20 m/s

Explanation:

Since the hoop is rolling on the floor so its total kinetic energy is given as

KE = \frac{1}{2}mv^2 + \frac{1}{2} I\omega^2

now for pure rolling condition we will have

v = R\omega

also we have

I = mR^2

now we will have

KE = \frac{1}{2}mv^2 + \frac{1}{2}(mR^2)\frac{v^2}{R^2}

KE = mv^2

now by work energy theorem we can say

W = KE_f - KE_i

842 J = mv_f^2 - mv_i^2

842 = 3(v_f^2) - 3\times 11^2

now solve for final speed

v_f = 20 m/s

3 0
2 years ago
A maple tree seed fell 180 centimeters straight toward the ground at a constant velocity. It moved that distance in 1.5seconds.
denis23 [38]

Answer: 1.2 m/s

Explanation:

Velocity V is defined as the variation of position of an object or body in time. So, if we know the distance the seed traveled and the time, we can calculate its velocity:

V=\frac{d}{t}

Where:

d=180 cm \frac{1 m}{100 cm}=1.8 m is the distance the maple seed traveled

t=1.5 s is the time

Then:

V=\frac{1.8 m}{1.5 s}

V=1.2 m/s This is the seed's velocity

7 0
3 years ago
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