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kozerog [31]
3 years ago
11

What are the factors that affect the rate of dissolution

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
<span>The amount of a component or solute that dissolves in a given volume of solvent at a certain temperature. </span>
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Which pair will for an ionic compound
vovikov84 [41]

Answer: A pair of elements will most likely form an ionic bond if one is a metal and one is a nonmetal. These types of ionic compounds are composed of monatomic cations and anions.

Explanation:

A pair of elements will most likely form an ionic bond if one is a metal and one is a nonmetal. These types of ionic compounds are composed of monatomic cations and anions.

Explanation:

The chart below shows monatomic ions formed when an atom loses or gains one or more electrons, and the ionic compounds they form. You can check your periodic table to see that the cations are monatomic ions formed from metals, and the anions are monatomic ions formed from nonmetals.

3 0
2 years ago
Which of the following is not the same as 2.97 milligrams? 0.0000297 kg, 0.00297 g, 0.297 ch
Travka [436]

the correct answer its  0.002975

4 0
3 years ago
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How many liters are equivalent to 645 mililiters
abruzzese [7]

Answer:

0.645 liters

Explanation:

THE QUESTION IS equivalent 0.645 Liters

6 0
3 years ago
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Why are outer electrons of some substances able to be removed by friction?
svlad2 [7]
<span>The outer electrons are not as tightly bound as ones closer to the nucleus</span>
8 0
3 years ago
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How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?
Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

=  heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0
3 years ago
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