When P1/P2 = C1/C2
and C is the molarity which = moles/volume
so, P1/P2 = [(mass1/mw)/volume] / [(mass2/mw)/volume]
P1/P2 = (mass1/mw)/1.5L / (mass2/mw)/1.5L
so, Mw and 1.5 L will cancel out:
∴P1/P2 = mass1 / mass2
∴ mass 2 = mass1*(P2 / P1)
= 0.278g * (78 bar / 62 bar)
= 0.35 g
∴ the quantity of argon that will dissolve at 78 bar = 0.35 g
According to the density of the liquid, we can get the mass of liquid is 70*0.85=59.5 g. So the total mass is 59.5+60.75=120.25 g.
Amines are organic compound obtained from ammonia by replacement of one or more hydrogen atoms by organic groups. If one of the 'H' atom of NH3 is replace by R = alkyl group, they are referred as primary amine. If two 'H' atoms of NH3 are replace by same or different alkyl group, they are referred as secondary amine.
Answer:
9.62moles of NH₃
Explanation:
Given parameters:
Number of moles of nitrogen = 4.81moles
Unknown:
Number of moles of NH₃ = ?
Solution:
To solve this problem, we need to establish a balanced reaction equation:
N₂ + 3H₂ → 2NH₃
Now, we can solve the problem by working from the known to the unknown.
1 mole of N₂ produced 2 moles of NH₃
4.81moles of N₂ will produce 2 x 4.81 = 9.62moles of NH₃
Concave mirrors, magnifying lens... sorry not sure about the rest
