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natka813 [3]
3 years ago
11

A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?

Physics
2 answers:
Alinara [238K]3 years ago
6 0
35000 joules. Kinetic energy = Ek = mV^2/2. m=700 kg. V = 10 m/s. Ek= 700 kg*100 m^2 7s^2/2. Ek = 35000 J
Ipatiy [6.2K]3 years ago
5 0

Answer:

Use equation for kinetic energy: Ek=mV²/2

m=700 kg

V=10m/s

Ek=700kg*100m²7s²/2

Ek=35000 J=35kJ

Explanation:

Hope this helps you

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(I will give brainliest whoever helps me !!)
lorasvet [3.4K]
C. Forces have mass and take up space
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3 years ago
Two blocks are the same size one block has a higher temperature than the other. Which describes the thermal energy of these bloc
shepuryov [24]
The block that has a higher temperature describes the thermal energy of these blocks. Thermal energy is a measure of internal energy - therefore, the block with the higher temperature has more internal energy than the block with the lower temperature, meaning it's thermal energy is greater. 
8 0
3 years ago
You are working on charge-storage devices for a research center. Your goal is to store as much charge on a given device as possi
zheka24 [161]

Answer:

Part A the answer is the dielectric constant.

Part B  Mica- mylar- paper- quartz

Explanation:

The capacity of a capacitor is given by

           C = ε ε₀ A / d

Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.

Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor

the flexibility of the material must also be taken into account

Part A the answer is the dielectric constant.

Pate B order the materials from best to worst

Mica. The best ever

Mylar Flexible

Paper Low capacity, low working voltage, flexible

Quartz high dielectric, but brittle

8 0
3 years ago
Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll
Len [333]

Answer:

Explanation:

initial velocity v = 2.1  x 10⁷ m/s

acceleration a = 5.1 x 10¹⁵ m /s²

horizontal distance covered = 5.5 x 10⁻² m

time taken to cover horizontal distance =  5.5 x 10⁻² / 2.1  x 10⁷

= 2.62 x 10⁻⁹ s .

b )

vertical distance travelled due to vertical acceleration

= 1/2 a t²

= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²

= 17.5 x 10⁻³ m

4 0
3 years ago
As a science fair project, you want to launch an 800 g model rocket st raight up and hit a horizontally moving target as it pass
fredd [130]

Sum the forces in the y (upward) direction

\sum F_y = ma

F_t +F_w = ma

15N - (0.800kg)(9.81m/s^2) = 0.800kg * a

a = 8.94 m/s^2

Applying the kinematic equations of linear motion we have that the displacement as a function of the initial speed, acceleration and time is

s = v_0t + \frac{1}{2} at^2

30 = 0 +\frac{1}{2} (8.94) t^2

t = 2.59 s

Again through the kinematic equation of linear motion that describes velocity as the change of displacement in a given time, we have to

v = \frac{d}{t} \rightarrow d = vt

d = (15m/s)(2.59s)

d = 38.85m

Therefore the horizontal distance between the target and the rocket should be 38.83m

4 0
3 years ago
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