The temperature of an object is dependant on its heat capacity and the rate at which heat can be removed from its surface. Heat conduction depends on the structure and capability of the atoms to move within the material and pass on their energy to other atoms. Some materials are better conductors then others that is why two objects can be in the same room but feel two different temperatures. It is also true if two object are at different temperatures and are in contact with one another they will reach the same temperature.
To solve the problem it is necessary to take into account the concepts of the kinetic equations for the description of the torque at the rate of force and distance.
By definition the torque is given by,
where,
For the problem in question the mass of the trophy is 1.64Kg and the distance of the tropeo to the board (the shoulder) is 0.655m
PART A) For part A, the torque with the given mass and the stipulated torque in the horizontal plane must be calculated as well,
For Newton's second law
PART B) For part B there is an angle of 26 degrees with respect to the horizontal, therefore to know the net torque it is necessary to know the horizontal component to the formed angle, that is,
Answer:
Explanation:
We shall apply law of conservation of momentum in space to know the velocity of combination after the impact
m₁v₁ = m₂v₂
.1 x 4 = ( 1 + .1 ) v₂
v₂ = .3636 m /s
1 )
Kinetic energy of the combination
= 1/2 x 1.1 x ( .3636)²
= 7.3 x 10⁻² J
2 )
Initial kinetic energy of the system
= 1/2 x 0.1 x 4²
= 0.8 J
Final kinetic energy of the system = 7.3 x 10⁻²
Loss of energy = .8 - .073
= .727 J
This energy was converted into internal energy of the system .
3 )
increase in entropy = dQ / T
Here dQ = .727 J
T = 300 ( Constant )
dQ / T = 2.42 X 10⁻³ J/K
The object that is subjected to a steady centripetal force moves in a circular motion. If this force suddenly disappear, the object moves in a direction tangential to the circle with respect to the last direction of the centripetal force.
Answer:
Charge on A is
Charge on B is , then
Distance between two charges = 16 cm = 0.16 m
Force F = 43 N
According to coulombs law force between tow charges is given by
, here K is constant which value is
So
so charge on A is
And charge on B is