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Sonja [21]
3 years ago
12

How temperature, surface tension and the diameter of the tube affect capillary action.​

Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

The surface tension acts to hold the surface intact. Capillary action occurs when the adhesion to the surface material is stronger than the cohesive forces between the water molecules. ... Water wants to stick to the glass and surface tension will push the water up, until the force of gravity prevents further rise.

Narrower tube openings allow capillary action to pull water higher

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Darcy is going to make raspberry jam for the county fair.
valentinak56 [21]

Answer:

She can make have 30 jars with raspberries in them with 50 left over.

Explanation:

1,700 divided by 55

30 equally

but 50 left over

This means that she can make have 30 jars with raspberries in them with 50 left over.

5 0
3 years ago
A(n) 1100 kg car is parked on a 4◦ incline. The acceleration of gravity is 9.8 m/s 2 . Find the force of friction keeping the ca
igomit [66]

Answer:

Force of friction, f = 751.97 N

Explanation:

it is given that,

Mass of the car, m = 1100 kg

It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.

From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.

f=mg\ sin\theta

f=1100\ kg\times 9.8\ m/s^2\ sin(4)

f = 751.97 N

So, the force of friction on the car is 751.97 N. Hence, this is the required solution.

3 0
3 years ago
under normal conditions describe how increasing the temperature affects the solubility of a typical salt
Eduardwww [97]
For many solids dissolved in liquid water, the solubility increases with temperature. The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.
8 0
3 years ago
A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa & absorbs energy of 84 J. Calculate the change i
leonid [27]

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

1W2 = P1 (V2 – V1)

= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ

4 0
3 years ago
A constant tone is being applied to a speaker. The voltage across the speaker is 5 volts. The voltage across the speaker is incr
lubasha [3.4K]

Answer:

decibel gain is 10 db

Explanation:

given data

voltage v1 =  5 volts

voltage v2 = 15 volts

to find out

decibel gain

solution

we have given that 5 volt voltage that is increase to 15 volts

so

we know here decibel gain formula that is

decibel gain = 20 log(v2/v1)   ....................1

put here value of v1 and v2  in equation 1

decibel gain = 20 log(15/5)

decibel gain = 20 log3

decibel gain = 20 × 0.4771

decibel gain = 9.54 db = approx 10 db

so decibel gain is 10 db

5 0
4 years ago
Read 2 more answers
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