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saveliy_v [14]
2 years ago
15

Austin invested $11,000 in an account paying an interest rate of 5.7% compounded quarterly. Assuming no deposits or withdrawals

are made, how much money, to the nearest dollar, would be in the account after 6 years?
Physics
2 answers:
Stels [109]2 years ago
5 0

Answer:

15448

Explanation:

A=11000(1.01425)^{24}

A=11000(1.01425)  

24

daser333 [38]2 years ago
3 0

Answer:

15448

Explanation:

Compounded Quarterly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+

n

r

​

)

nt

Compound interest formula

P=11000\hspace{35px}r=0.057\hspace{35px}t=6\hspace{35px}n=4

P=11000r=0.057t=6n=4

Given values

A=11000\left(1+\frac{0.057}{4}\right)^{4(6)}

A=11000(1+

4

0.057

​

)

4(6)

Plug in values

A=11000(1.01425)^{24}

A=11000(1.01425)

24

Simplify

A=15448.0290759

A=15448.0290759

Use calculator

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A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
KengaRu [80]

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m

Therefore, the length of the wire is 134.62 m.

6 0
2 years ago
Your car is stalled in the middle of a large patch of ice (assumed to be frictionless). You have a friend that has thrown a rope
Gnoma [55]

Answer:

The time depends on the distance that they have to travel

x(t) = \frac{0.3846t^{2} }{2}

Explanation:

The only horizontal force exerts over the car and you, it is the force that your friend is applied

Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus

\sum{F} = ma

        550 = 1430a

            a = 0.3846 m/s2

             

The car and you have a motion under constant acceleration, then theirs position to a time-based is:

x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}

By the initial conditions

x(t) = \frac{at^{2} }{2}

x(t) = \frac{0.3846t^{2} }{2}

The time depends on the distance that they have to travel  

7 0
3 years ago
A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m,
babymother [125]

Answer:

19372.29 N

Explanation:

Kinetic Energy of the man = Work done by the average resistive force of water.

mg(H+d) = F×d............................ Equation 1

where, m = mass of the woman, H = Height of the platform, d = depth of water reached, F = average resistive force exerted by water.

make F the subject of the equation,

F = mg(H+d)/d...................... Equation 2

Given: m = 65.0 kg, H = 10 m, d = 3.4 m, g = 9.8 m/s²

Substitute into equation 2

F = 65(9.8)(100+3.4)/3.4

F = 19372.29 N

8 0
3 years ago
Part b what is the particle's speed at t=4.5s ? express your answer using two significant figures.
Alex777 [14]
20 times the number of hours
3 0
3 years ago
a satellite is revolving around the sun in a circular orbit with uniform velocity v. if the gravitational force suddenly disappe
cestrela7 [59]

Answer:

when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.

7 0
3 years ago
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