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saveliy_v [14]
3 years ago
15

Austin invested $11,000 in an account paying an interest rate of 5.7% compounded quarterly. Assuming no deposits or withdrawals

are made, how much money, to the nearest dollar, would be in the account after 6 years?
Physics
2 answers:
Stels [109]3 years ago
5 0

Answer:

15448

Explanation:

A=11000(1.01425)^{24}

A=11000(1.01425)  

24

daser333 [38]3 years ago
3 0

Answer:

15448

Explanation:

Compounded Quarterly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+

n

r

​

)

nt

Compound interest formula

P=11000\hspace{35px}r=0.057\hspace{35px}t=6\hspace{35px}n=4

P=11000r=0.057t=6n=4

Given values

A=11000\left(1+\frac{0.057}{4}\right)^{4(6)}

A=11000(1+

4

0.057

​

)

4(6)

Plug in values

A=11000(1.01425)^{24}

A=11000(1.01425)

24

Simplify

A=15448.0290759

A=15448.0290759

Use calculator

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vampirchik [111]

Answer:

\large \boxed{\text{30 rev/s}}

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

If momentum is conserved,

I₁ω₁ = I₂ω₂

Data:

 I₁ = 3.5    kg·m²s⁻¹

ω₁ = 6.0    rev·s⁻¹

 I₂ = 0.70 kg·m²s⁻¹

Calculation:

\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}

8 0
4 years ago
Calculate the speed of a train that traveled 810 kilometers in 9 hours.
Naya [18.7K]

Answer:

90 kilometers an hour

let me know if I'm wrong

8 0
3 years ago
Part A
geniusboy [140]

Answer:

a) b = -5

b) slope = 3/2

Explanation:

a) The equation of a line is given as y = mx + b, where m is the slope of the line and b is the intercept on the y axis.

Given that y = 3x + b and it passes through the point (2, 1). Hence when x = 2, y = 1. Therefore, substituting for x and y:

1 = 3(2) + b

1 = 6 + b

b = 1 - 6

b = -5

b) The equation of a line passing through two points (x_1,y_1) and x_2,y_2 is given by:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of the line passing through the two points (0,3) and (4,9) is:

y-3=\frac{9-3}{4-0}(x-0)\\ \\y-3=\frac{3}{2}x\\ \\y = \frac{3}{2}x+3

Comparing y = (3/2)x + 3 with y = mx + b, the slope (m) is 3/2

4 0
3 years ago
The load across a 12 v battery consists of a series combination of three resistors 45 ω, 55 ω, and 35 ω. what is the total resis
zubka84 [21]
For n resistors in series, the equivalent resistance is given by the sum of the resistances:
R_{eq} = R_1 + R_2 + ... + R_n

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
R_{eq}=45 \Omega + 55 \Omega + 35 \Omega =135 \Omega
5 0
4 years ago
Describe how you expect the waveform and the sound you hear changes when you hit the tuning fork harder.
myrzilka [38]

Answer:

In a tuning fork, two basic qualities of sound are considered, they are

1) The pitch of the waveform: This pitch depends on the frequency of the wave generated by hitting the tuning fork.

2) The loudness of the waveform: This loudness depends on the intensity of the wave generated by hitting the tuning fork.

Hitting the tuning fork harder will make it vibrate faster, increasing the number of vibrations per second. The number of vibration per second is proportional to the frequency, so hitting the tuning fork harder increase the frequency. From the explanation on the frequency above, we can say that by increasing the frequency the pitch of the tuning fork also increases.

Also, hitting the tuning fork harder also increases the intensity of the wave generated, since the fork now vibrates faster. This increases the loudness of the tuning fork.

6 0
4 years ago
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