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3 years ago

1.05 MEASURING PHYSICAL PROPERTIES LAB REPORT

Physics

1 answer:

Nana76 [90]3 years ago

4 0

Answer:

Objective(s): In your own words, what was the purpose of this lab?

The purpose of this lab is to get us familiar with the physical properties of different types of materials that are used for building.

Hypothesis: In this section, include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.

If we use clay brick to build the roof of the house, then the temperature inside the house will remain cooler.

If we use wood to build the walls and floors of the house, then the temperature inside the house will remain cooler.

If we use nickel to bring electricity into the home, then it will allow electricity to flow into the home at a faster rate.

If we use iron to construct the latches on the windows and doors, then the magnetism will keep the latches secure.

Procedure: The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome.

Using the summary questions, clearly define the dependent and independent variables of the experiment.

Data: Record the results of each of your physical property tests in the table below.

Wood _ 3/10 _0 _0.12 W/(m·K) _0 S/m _ 4 g/cm3

Clay Brick _ 2/10 _1 _0.6 W/(m·K) _ 0 S/m _ 5.88235 g/cm3

Iron _ 4/10 _10 _80 W/(m·K) _1x107 S/m _9.09091 g/cm3

Aluminum_ 7/10 _ 0 _235 W/(m·K) _ 3.8x107 S/m _ 6.66667 g/cm3

Copper _ 6/10 _0 _400 W/(m·K) _3.8x107 S/m _9.52381 g/cm3

Nickel _ 5/10 _7 _ 91 W/(m·K) _1.4x107 S/m _9.43396 g/cm3

Conclusion: Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

Using two to three sentences, summarize what you investigated and observed in this lab.

In this, I investigated the effect that different types of physical properties had on six different materials. I also investigated which materials would be the best to build a house.

2. What building material did you use to build your house? Did your results support or fail to support your hypotheses?

For the roof of my house, I used clay bricks. For the walls and floors of the house, I used wood. To bring electricity into the home I used nickel. To construct the latches on the windows and doors, I used iron. My results supported my hypotheses because clay bricks and wood had the lowest thermal conductivity rates, nickel had the second highest electricity conductivity rate, and iron had the highest magnetism rate.

3. What were the densities of the materials you chose for the walls and floor for the home in Tiny World? Why do you think a building material's density is important when building homes or architectural structures?

The density of the material I chose for the walls and floors for the home in Tiny World was 4 g/cm3 (Wood). I think a buildings material density is important when building homes or architectural structures because in order for that structure to stay stable the materials that are used must be dense. If the materials are not dense, the structure would most likely collapse if it is placed under too much pressure.

4. Why wouldn’t you choose wood or aluminum for the latches on your house?

I wouldn’t choose wood or aluminum for the latches on my house because neither of those two materials are magnetic.

5. Which material has the highest thermal conductivity? Which material has the highest electrical conductivity? Explain why thermal and electrical conductivity is so high with this material.

Copper has the highest thermal conductivity. Aluminum and copper have the highest electrical conductivity. Thermal conductivity is high in copper because copper is a very thin type of material, and this allows heat to pass through it easily. Electric Conductivity is high in both aluminum and copper because they are both a very thin type of metal and because they are both so thin, electricity will pass through them quickly.

I'm sorry if any of the answers are wrong, this was just assigned to me and my teacher hasn't graded it yet.

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A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9

Black_prince [1.1K]

Answer:

$C = 46.891 \mu F$

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

$s = \frac{P}{P.F} < COS^{-1} 0.65$

$S = \frac{1250}{0.65} < 49.45$

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

$P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]$

solving for $Q_{new}$

$Q_{new} = P tan [cos^{-1} P.F new]$

$Q_{new} = 1250 [tan[cos^{-1}0.9]]$

$Q_{new} = 605.40 VARS$

$Q_C = Q - Q_{new}$

$Q_C = 1461 - 605.4 = 855.6 vars$

$Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C$

$C = \frac{Q_C}{ v_{rms}^2 \omega}$

$C = \frac{855.6}{220^2 \times 2\pi \times 60}$

$C = 4..689 \times 10^{-5}$ Faraday

$C = 46.891 \mu F$

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4 years ago

"Stop to Think 16.1" on page 423 of your textbook. Also, for situation (a), descibe what happens to the speed of the wave, the f

garik1379 [7]

Answer:

wave speed= constant

frequency = increase

wavelength = decrease

Explanation:

Solution:

- The three basic parameters of a wave are speed, frequency and wavelength. These three parameters are related to each other by an expression:

v = f * λ

Where,

- v is the speed of the wave in m/s.

- f frequency of the wave in Hz.

- λ wavelength of the wave in m

- We are asked how would each of these parameter change if we move the hand up and down faster. The hand moves from a crest to trough faster than before and back again. We can see that the time between a cycle has decreased; hence, frequency f increases. Consequently, we can see that wave speed v remains constant - the medium of transfer of wave energy - remains same. Then from our relation above if we hold speed constant and increase f then the wavelength λ would have to decrease.

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3 years ago

A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by

borishaifa [10]

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

Y = 78.13 x 10⁹ Pa = 78.13 GPa

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Consider the average speed of a runner who jogs around a track four times. The distance (400m) remains constant for each lap. Ho

Yuki888 [10]

D) decreases, inverse

Explanation:

The average speed of each lap decreases. This is an example of an inverse relationship.

Speed is the rate of change of distance with time. In calculating the average speed, we should understand that the total length of path is taken into consideration and so is the total time taken.

Average speed = $\frac{total distance}{total time}$

It was explained that after every 5 seconds the speed of the runner becomes slower.

There is definitely an inverse relationship between average speed and the total time taken.

An inverse relationship is such that as one variable increases, the other diminishes.

As average speed reduces the time taken increases.

learn more:

Speed brainly.com/question/1386181

#learnwithBrainly

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Luda [366]

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