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muminat
2 years ago
9

What s this pls helpppppp

Mathematics
2 answers:
Nutka1998 [239]2 years ago
6 0

Answer:

3

Step-by-step explanation:

AlladinOne [14]2 years ago
6 0
The answer should be 3 !!
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Suppose that the function f is defined. , for all real numbers, as follows.
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Step-by-step explanation:

Given function is:   \left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.

For f(-5),  the value of x is -5, which is not equal to -2.

So,  f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}

For f(-2),  the value of x is -2.

So,  f(-2)= -1

For f(4),  the value of x is 4, which is not equal to -2.

So,  f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0

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3 years ago
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360

Step-by-step explanation:

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2 years ago
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