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nata0808 [166]
2 years ago
12

What occurs during a solar elcipse

Chemistry
2 answers:
djverab [1.8K]2 years ago
8 0

Answer:

A solar eclipse happens when the moon moves in front of the Sun as seen from a location on Earth. During a solar eclipse, it gets dimer and dimmer outside as more and more of the Sun is covered by the Moon. During a total eclipse, the entire Sun is covered for a few minutes and it becomes very dark outside. The temperature outside also drops.

solong [7]2 years ago
7 0

Answer:

the moon gets infront of the sun

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Using the periodic table as a reference, which elements could bond to form a compound most like NaCl?
pychu [463]

<u>step</u><u> </u><u>by</u><u> </u><u>step</u>

Na(sodium)=2.8.1

Cl (Chlorine)=2.8.7. sodium will give the chlorine the 1 valence electron to become stable ions.

<u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<u>p</u><u>o</u><u>t</u><u>t</u><u>a</u><u>s</u><u>i</u><u>u</u><u>m</u><u>. </u><u>(</u><u>2</u><u>.</u><u>8</u><u>.</u><u>8</u><u>.</u><u>1</u><u>)</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>F</u><u>l</u><u>o</u><u>u</u><u>r</u><u>i</u><u>n</u><u>e</u><u>(</u><u>2</u><u>.</u><u>7</u><u>)</u>

4 0
3 years ago
Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance
ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

8 0
3 years ago
During a solar flare, it is most likely that
ludmilkaskok [199]

Answer:

During a solar flare, the built up magnetic energy n the solar atmosphere is released at once. If a strong solar flare hits the earth, it is most possible that it will destroy the electronics. It is not expected to effect any human beings unless they are travelling towards the outer space are living at higher altitudes.

It can lead to skin can in case of extreme exposures.

I hope the answer is helpful.

Thanks for answering.

6 0
2 years ago
Read 2 more answers
QUESTION 1 (POLL)
Airida [17]

Answer:

They stay the same

Explanation:

4 0
3 years ago
Which list of elements consists of a metal, a metalloid, and a nonmetal?
Irina18 [472]

Answer:

Sn, Si, C

Explanation:

8 0
3 years ago
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