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vredina [299]
2 years ago
7

A child on a sled has a combined mass of 54 kg. At the top of a 2.7 meter hill, the sled has a

Physics
1 answer:
leonid [27]2 years ago
5 0

Answer:

8.78?m/s

Explanation:

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Which factors affect the resistance of a material? Check all that apply.
shutvik [7]

Answer: Length, thickness, and temperature

Explanation:

I did it

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3 years ago
How do earthquakes affect earths surface?
ivanzaharov [21]
Some of the reasons that can cause can earthquake are volcanic eruptions, the grinding of tectonic plates beneath the earth's crust and violent explosions which can be artificially induced as well. No matter what the reason is, earthquakes affect the environment and earth's surface. Noticeable cracks have formed on the earth's surface after earthquakes. If the tremors are violent, it can result in the destruction of landscapes. The mountains become prone to land sliding. the glacier's become a threat because of fear of avalanches. tsunamis which are earthquakes in the ocean bed can cause heavy flooding which causes water to cross all boundaries and shores and flood entire cities. Earthquakes caused by volcanoes can result in the spewing of so much lava that it may spill everywhere and cool changing the surface of the earth geologically as well as the ash causing aerial pollution.
4 0
3 years ago
If the period of a wave is 0.05 s, then what is its frequency?
yKpoI14uk [10]
Frequency = 1/time period = 1/0.05 = 20s^-1. 
8 0
3 years ago
Read 2 more answers
Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur
dimulka [17.4K]

Answer:

-1.7908787542\times 10^{-9}\ C

3.4260289211\times 10^{-9}\ C

1.7908787542\times 10^{-9}\ C

1.6351501669\times 10^{-9}\ C

Explanation:

r = Radius

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Electric field is given by

E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C

The charge is -1.7908787542\times 10^{-9}\ C

Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C

The charge is 3.4260289211\times 10^{-9}\ C

The charge inside will have the polarity changed

q=+1.7908787542\times 10^{-9}\ C

Outside the charge will be

3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C

3 0
3 years ago
How many pets do you have???!!!??
jasenka [17]

Answer:

Right now I have three.

Explanation: Thanks for the points luv ^-^.

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3 years ago
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