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sukhopar [10]
3 years ago
6

In which case is the speed of laser light the slowest relative to the observer? a person walking in the street and who sees lase

r light emitted from a low‑speed car that moves in the same direction as the person a student sitting in the classroom and who see laser light from the pointer used by the instructor laser light emitted from a high‑speed aircraft and detected by another high‑speed aircraft traveling in the opposite direction a person who sees laser light passing through a bucket full of water it is the same for all of the above
Physics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

<em>a person who sees laser light passing through a bucket full of water.</em>

Explanation:

According to relativity, the speed of light is the same irrespective of the relative speed between the source, and the observer. The only exception is when light travel from a less dense medium to a denser medium as in air into the bucket full of water. So the speed of light is slowest relative to the observer in the laser that passes through the bucket of water.

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Compare the maximum rate of heat transfer to the basal metabolic rate by converting a bmr of 88 kcal/hr into watts. what is the
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Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, 1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}

1\ kcal/h=1.16\ J/sec

J/sec is nothing but watts.

So, 1\ kcal/h=1.16\ watts

and 88\ kcal/h=88\times 1.16\ watts = 102.08\ watts

So, it can be seen that the body can accommodate a modes amount of activity in hot weather but strenuous activity would increase the metabolic rate above the body's ability to remove heat.

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3 years ago
I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.
Tcecarenko [31]

Answer:It’s 5 I believe

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2 years ago
Field of psychology that studies the behavior of shoppers
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3 years ago
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

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When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

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Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

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All matter is composed of atoms, indestructible building blocks.
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