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Crazy boy [7]
2 years ago
9

I need help plz and thank you. This is past due and I will mark brainiest

Physics
2 answers:
aleksandr82 [10.1K]2 years ago
8 0

Answer:

reproduced in print form for non-profit educational use with. Reading ... 2. I had them in my backpack. 3. Help me look for them. 4. We don't want to get lost. 5. I'm so ... Commas set off introductory words, such as yes, no, and thank you. Rewrite ... Correct each run-on sentence below by writing it as a compound sentence. 1.

Explanation:

max2010maxim [7]2 years ago
5 0
The person above me is right
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True or false? If an element can form covalent bonds then it will never be involved in ionic bonding.
vladimir2022 [97]

Answer:

true

Explanation:

because the bonds in that element can only be shared but not transferred , but sometimes it depends on the element

7 0
3 years ago
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Why electric potential of earth is taken to be zero?
stiv31 [10]
The ground is very large an small amount of electric charge wont affect it
4 0
3 years ago
Number these from least (1) to most (5) mass ?
alisha [4.7K]

Answer:

1. A feather

2. A baseball

3. A small car

4. A truck

5. A large train

Explanation:

5 0
2 years ago
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A person kicks a ball, giving it an initial velocity of 20.0 m/s up a wooden ramp. When the ball reaches the top, it becomes air
Bess [88]

Answer:

Explanation:

given,

initial velocity of the ball = 20 m/s

angle of ramp = 22°

ball travel at a distance  = 5 m

a) for friction less  

  \dfrac{1}{2}mv^2 = \dfrac{1}{2}mu^2 - mgh

             v^2 = u^2 - 2gh

             v = \sqrt{u^2- 2 g h cos 22^0}

             v = \sqrt{20^2- 2\times 9.8 \times 5 cos 22^0 }

                    v = 17.58 m/s

b) considering the friction

  \dfrac{1}{2}mv^2 = \dfrac{1}{2}mu^2 - mgh-\mu_kmgl

             v^2 = u^2 - 2gh-2\mu_kmgl

             v = \sqrt{u^2- 2 g h cos 22^0-2\mu_kgl}

             v = \sqrt{20^2- 2\times 9.8 \times 5 cos 22^0-2\times 0.15\times 9.8 \times 5 }

                   v = 17.16 m/s

7 0
3 years ago
A small ball with mass 1.20 kg is mounted on one end of a rod 0.860 m long and of negligible mass. The system rotates in a horiz
Rufina [12.5K]

Answer:

0.88752 kgm²

0.02236 Nm

Explanation:

m = Mass of ball = 1.2 kg

L = Length of rod = 0.86 m

\theta = Angle = 90°

Rotational inertia is given by

I=mL^2\\\Rightarrow I=1.2\times 0.86^2\\\Rightarrow I=0.88752\ kgm^2

The rotational inertia is 0.88752 kgm²

Torque is given by

\tau=FLsin\theta\\\Rightarrow \tau=2.6\times 10^{-2}\times 0.86sin90\\\Rightarrow \tau=0.02236\ Nm

The torque is 0.02236 Nm

5 0
3 years ago
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