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2 years ago

How long would it take someone jogging at 2.4 m/s to travel 2300 m?

Physics

1 answer:

Ber [7]2 years ago

7 0

Answer:

958 Second or 15 minute and 58 second approximately 16 minutes

Explanation:

m / m/s

2300/2.4 = 958 second

958/60 = 15 minutes and 58 seconds approximately 16 minutes

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You are given four resistors, 2 ohms, 3 ohms, 5 ohms, and 10 ohms. Your friend say you can connect them so you obtain an equival

AlexFokin [52]

If we will connect the resistors 2ohms, 3ohms, 5ohms in series and the 10ohms resistance parallel then we get equivalent resistance of 5 ohms.

The equivalent circuit is,

R equivalent for the series connection is,

$\begin{gathered} Req(S)=2+3+5=10ohms \\ Now,\text{ } \\ Req\text{ }for\text{ }10\text{ }ohms\text{ }and\text{ }10\text{ }ohms\text{ }is, \\ \frac{1}{Req}=\frac{1}{10}+\frac{1}{10}=\frac{2}{10}=\frac{1}{5} \\ So, \\ Req=5\text{ ohms} \end{gathered}$

The equivalent resistance is 5 ohms.

So your friend is saying true.

6 0

1 year ago

Consider a golf club hitting a golf ball. To a good approximation, we can model this as a collision between the rapidly moving h

vekshin1

Answer:

1. 8.0kg * m/s

2. The same as before the collision

3. The force will decrease

4. 14 m/s

6 0

3 years ago

What is unique about Neptune's discovery?

ale4655 [162]

Answer:

the answer is

B)It was the first planet located through mathematical calculations

7 0

3 years ago

A small, 150 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 5.00 kg cart at rest. After th

NemiM [27]

Answer:

Mass of larger cart will be 0.0213 m /sec

Explanation:

We have given mass of small cart $m_1=150gram=0.150kg$

Initial velocity of small cart $v_{1i}=1.6m/sec$

Mass of larger block $m_2=5kg$

Initial velocity of larger cart $v_{2i}=0m/sec$

After the collision velocity of smaller cart $v_{1f}=-0.890m/sec$

Now according conservation of momentum

$m_1v_{1i}+m_2v_{2i}=m_1v{1f}+m_2v_{2f}$

$0.150\times 1.6+5\times 0=0.150\times -0.890+5\times v_{2f}$

$5\times v_{2f}=0.1065$

$v_{2f}=0.0213m/sec$

5 0

3 years ago

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper. If the magneti

nevsk [136]

Answer:

Explanation:

The magnetic moment of the coil M = current x area of loop

= I x L x L

M = L² I .

Magnetic field = B

Torque = M x B

= MB sinθ where θ is angle between M and B . Direction of M is perpendicular to face of loop

Torque = MB sin90

= MB

= L² I B .

3 0

3 years ago