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Mila [183]
3 years ago
10

If the amplitude of a sound wave is made 3.0 times greater, by what factor will the intensity increase? Express your answer usin

g two significant figures. I/I0I / I 0 = nothing Request Answer Part B If the amplitude of a sound wave is made 3.0 times greater, by how many dB will the sound level increase? ββ = nothing dB Request Answer Provide Feedback
Physics
1 answer:
vesna_86 [32]3 years ago
4 0

Answer:

Calculating Sound Intensity Levels: Sound Waves

Calculate the sound intensity level in decibels for a sound wave traveling in air at 0ºC

and having a pressure amplitude of 0.656 Pa.

Explanation:

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How to Convert N/m2 to N/cm2 ?​
Brut [27]

1 newton / square metre =0.0001 newton / square centimetre

Formula = divide the pressure value by 10000

5 0
3 years ago
Test populations are studied. Population one is found to obey the differential equation dy1/da=o.2y1 and the population two obey
oksano4ka [1.4K]

Answer:

Population 1 indicates growth while Population 2 indicates a declining population

Explanation:

Here, using the given rate of change of the population, we want to determine which of the two is growing and which is declining

From the rate of change of both, we can determine this. Looking at the differential equation for the first one, we can see that it is of positive value. Looking at the differential equation for the second one. we can see it is of negative value

While a positive change rate indicates growth, a negative change rate will indicate otherwise

Hence, we can conclude that the one with a negative rate change will indicate a declining population

8 0
3 years ago
7 A steel sphere is released from a height
alisha [4.7K]

Answer:

C 3.3 s

Explanation:

Given:

Δy = 9 m

v₀ = 0 m/s

a = ⅙ (9.8 m/s²) = 1.63 m/s²

Find: t

Δy = v₀ t + ½ at²

9 m = (0 m/s) t + ½ (1.63 m/s²) t²

t = 3.3 s

4 0
3 years ago
Which of the following units is an SI base unit?
Jobisdone [24]
<span>B. Kilogram
_________</span>
4 0
3 years ago
A 5.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
masya89 [10]

Answer:

F=124.03 N

Explanation:

Given data

mass m=5.00 kg

y(t)=(2.80 m/s)t+(0.61m/s³)t³

To find

Force F at t=4.10 s

Solution

As

y(t)=(2.80m/s)t+(0.61m/s^{3} )t^{3}

derivative with respect to time we get

\frac{dy(t)}{dt} =v(t)=2.80+1.83t^{2}

again derivative with respect to time to get acceleration

\frac{dv(t)}{dt}=a(t)=3.66t

at t=4.10 s then a(t) is

a=3.66(4.10)

a=15.006 m/s²

Now to use Newton law to find force in y direction

F-mg=ma\\F=mg+ma\\F=(5.00kg)(9.8m/s^{2} )+(5.00kg)(15.006m/s^{2} )\\F=49N+75.03N\\F=124.03N

8 0
3 years ago
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