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Mila [183]
3 years ago
10

If the amplitude of a sound wave is made 3.0 times greater, by what factor will the intensity increase? Express your answer usin

g two significant figures. I/I0I / I 0 = nothing Request Answer Part B If the amplitude of a sound wave is made 3.0 times greater, by how many dB will the sound level increase? ββ = nothing dB Request Answer Provide Feedback
Physics
1 answer:
vesna_86 [32]3 years ago
4 0

Answer:

Calculating Sound Intensity Levels: Sound Waves

Calculate the sound intensity level in decibels for a sound wave traveling in air at 0ºC

and having a pressure amplitude of 0.656 Pa.

Explanation:

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Imagina que compras una placa rectangular de metal de 2mm de alto, 10mm de ancho x 50mm de largo, y una masa de 0.02kg. El vende
shusha [124]

Answer:

Densidad de la placa = 20 g/cm³.

La placa no es de oro.

Explanation:

Para encontrar la densidad de la placa rectangular primero debemos hallar su volumen:

V = 2 mm*10 mm*50 mm = 1000 mm^{3}*\frac{1 cm^{3}}{(10 mm)^{3}} = 1 cm^{3}      

Ahora, encontremos al densidad de la placa:

d = \frac{m}{V} = \frac{20 g}{1 cm^{3}} = 20 g/cm^{3}

Dado que la densidad del oro es 19.32 g/cm³ y que la densidad de la placa rectangular calculada es 20 g/cm³, podemos decir que dicha placa no es de oro.                  

Espero que te sea de utilidad!

6 0
3 years ago
An egg is cracked/broken. Is this egg experiencing a Physical or Chemical change? (Hint: is it still an egg?)
Leokris [45]
The asnwer is the first choice! and lol yes its still luv ;)
4 0
3 years ago
Can Someone please help me! <br><br> What is deposition
7nadin3 [17]

Deposition is the geological process in which sediments, soil and rocks are added to a landform or landmass

7 0
2 years ago
Read 2 more answers
Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t
zlopas [31]

Answer:

y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

Explanation:

As we know that the wave equation is given as

y = A sin(\omega t - k x + \phi_0)

now we have

A = 0.19 m

\lambda = 2.6 m

so we have

k = \frac{2\pi}{\lambda}

k = \frac{2\pi}{2.6}

k = 2.42  per m

also we have

T = 1.2 s

so we have

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{1.2}

\omega = 5.23 rad/s

now we know that at t = 0 and x = 0 wave is at y = 0.19 m

so we have

\phi_0 = \frac{\pi}{2}

so we have

y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

6 0
3 years ago
The parallax of heavenly body measured from two points diametrically opposite on the equator of the earth is 1.0 min. If the rad
algol13

Answer:

OHJIPUBGV008 NIMO,7TBVYU

Explanation:

GGGGGGGGGGGGGGGGGGGGGGGGGGGTFV78BYON8I0OIJJIMONJU

5 0
3 years ago
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