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3 years ago

Whats the ph for a solution poh4 9.78 concentration of solution

Chemistry

1 answer:

MrMuchimi3 years ago

3 0

Answer:

4.22

Explanation:

According to the question, the pOH of the solution is 9.78. You may recall that pOH is the hydroxide concentration of a solution.

Also pOH = -log[OH^-]. Hence the pOH is obtained from the hydroxide ion concentration.

Finally, pH + pOH =14

Hence;

pH = 14-pOH

pH= 14-9.78 = 4.22

pH= 4.22

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the largest is francium, Z=87 , or caesium, Z=55 ; and the smallest is definitely helium, Z=2 .

Explanation:

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3 years ago

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

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Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

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3 years ago

The number of possible different orbital shapes for the third energy level is

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Answer:

option c) 3 is the correct option

Explanation

as we know that 3rd principal energy level contains 3 sub levels,which are named as s,p and d. These sub levels further contain different numbers of orbitals,

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Answer:

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Answer:

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Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc.

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3 years ago