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2 years ago

Which element has the greatest electronegativity? B C Cl

Chemistry

1 answer:

mihalych1998 [28]2 years ago

3 0

Chlorine. Electronegativity rises as you go up and to the right on the periodic table.

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At 25°C and constant pressure, carbon monoxide gas combines with oxygen gas to give carbon dioxide gas with the evolution of 10.

stealth61 [152]

Answer : The value of $\Delta H$ for the reaction is, -565.6 kJ

Explanation :

First we have to calculate the molar mass of CO.

Molar mass CO = Atomic mass of C + Atomic mass of O = 12 + 16 = 28 g/mole

Now we have to calculate the moles of CO.

$\text{Moles of }CO=\frac{\text{Mass of }CO}{\text{Molar mass of }CO}=\frac{1g}{28g/mole}=\frac{1}{28}mole$

Now we have to calculate the value of $\Delta H$ for the reaction.

The balanced equation will be,

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

From the balanced chemical reaction we conclude that,

As, $\frac{1}{28}mole$ of CO release heat = 10.1 kJ

So, 2 mole of CO release heat = $2\times 28\times 10.1=565.6kJ$

Therefore, the value of $\Delta H$ for the reaction is, -565.6 kJ (The negative sign indicates the amount of energy is released)

4 0

3 years ago

HELP FAST!!!

AfilCa [17]

Answer:

the fourth one I think....m

Explanation:

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7 0

2 years ago

What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog

anastassius [24]

The coefficient for hydrogen in the balanced equation of solid molybdenum(iV) oxide with gaseous hydrogen is 2

Explanation

Coefficient is defined to as a number in front of a chemical formula in a balanced chemical equation.

The reaction of molybdenum (iv) oxide with gaseous hydrogen is as below,

MoO2 + 2 H2→ Mo +2 H2O

From balanced equation above the coefficient for H2 is 2 since the number in front of H2 is 2

3 0

3 years ago

Arjun placed a salt cube in a cup of water. He wonders whether stirring the water will make the salt cube

Ilya [14]

Explanation:

Yes...the molecules would get warmer has they collide into each Other...

8 0

3 years ago

What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?

____ [38]

Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = 0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

Read more on Brainly.com - brainly.com/question/10606064#readmore

5 0

2 years ago