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4vir4ik [10]
3 years ago
6

Why are prefixes not needed in naming ionic compounds?

Chemistry
1 answer:
kari74 [83]3 years ago
6 0

Answer:

when naming ionic compounds — those are only used in naming covalent molecular compounds. Do NOT use prefixes to indicate how many of each element is present; this information is implied in the name of the compound. since iron can form more than one charge. Ionic Compounds Containing a Metal and a Polyatomic Ion.

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Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC
sesenic [268]

Answer:

a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

%IC = (1 - e^{-0.25*(x_A - x_B)^2}) *100%

Where x_A - x_B is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. x_{Ti} = 1.5

x_{O} = 3.5

%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})*100%

%IC = 63.2%

b. x_{Zn} = 1.6

x_{Te} = 2.1

%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})*100%

%IC = 11.7%

c. x_{Cs} = 0.7

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})*100%

%IC = 73.3%

d. x_{In} = 1.7

x_{Sb} = 1.9

%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})*100%

%IC = 0.995 %

e. x_{Mg} = 1.2

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})*100%

%IC = 55.5%

4 0
3 years ago
How many grams of NaCl are required to make 150.0 mL of a 5.000 m solution
Oksi-84 [34.3K]

The  grams   of NaCl  that are required  to  make  150.0 ml of  a  5.000 M  solution is  43.875 g


calculation

Step 1:calculate  the  number of moles

moles =  molarity  x volume  in L

volume  = 150 ml / 1000 = 0.15 L

= 0.15 L  x 5.000  M  = 0.75  moles

Step 2:  calculate mass

mass =  moles x  molar mass

molar mass  of NaCl = 23 + 35.5 = 58.5 mol /L


mass is therefore =0.75  moles  x 58.5  mol /l =43.875 g

4 0
3 years ago
Read 2 more answers
Which two structures would provide a positive identification of a plant cell under a microscope
katovenus [111]
Lysosome, central vacuole
7 0
3 years ago
Read 2 more answers
CaC2 + 2H2O → C2H2 + Ca(OH)2 If 2.8 moles of CaC2 are consumed in this reaction, how many grams of H2O are needed?
Strike441 [17]

Answer:

Cac2 is a answer please mark me brainliest

8 0
3 years ago
How many grams of KBr is required to prepare 100 mL of<br> 2.0 M KBr solution?
sesenic [268]

Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)

= 0.2 mol

We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

We can now calculate the grams by using grams=mol x molar mass

119.023g/mol x 0.2mol

= 23.8046 g

=23.8g (rounded to 1decimal place)

4 0
3 years ago
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