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4vir4ik [10]
3 years ago
6

Why are prefixes not needed in naming ionic compounds?

Chemistry
1 answer:
kari74 [83]3 years ago
6 0

Answer:

when naming ionic compounds — those are only used in naming covalent molecular compounds. Do NOT use prefixes to indicate how many of each element is present; this information is implied in the name of the compound. since iron can form more than one charge. Ionic Compounds Containing a Metal and a Polyatomic Ion.

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Explain why the C―Ha bond is much more acidic than the C―Hb bond in pentan-2-one. Select the single best answer. 253 Ha is less
mafiozo [28]

Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

3 0
3 years ago
the half of an oxidation-reduction reaction shows the iron gains. what does this electron gain mean for iron.
Nataly [62]

The correct answer is option C, that is, it is reduced.

In reduction and oxidation reactions, reduction refers to the loss of an oxygen atom from a molecule or the gaining of one or more electrons. A reduction reaction is observed from the perspective of the molecule being reduced, as when one molecule gets reduced, another one gets oxidized. The complete reaction is called a redox reaction.

In the given case, iron gains electrons mean that it is reduced.  


3 0
3 years ago
Please help!! Why is the following Electron Configuration incorrect for Aluminium?
Margarita [4]

Answer:

3s^1 would be 3s^2

Explanation:

5 0
3 years ago
A 3.5-g sample of colorado oil shale is burned in a bomb calorimeter, which causes the temperature of the calorimeter to increas
Lubov Fominskaja [6]
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3 0
3 years ago
Read 2 more answers
1. A 50 gram sample of a radioisotope decays to 12.5 grams in 14.4 seconds. What is
stiv31 [10]

Answer:

Half life = 7.2 seconds

Explanation:

from \: decay \: equation \\ 2.303 log( \frac{n.}{nt} )  = kt \\ 2.303 log( \frac{50}{12.5} )  = k \times 14.4 \\ k =  \frac{2.303 log( \frac{50}{12.5} )}{14.4}  \\ k = 0.096288 {s}^{ - 1}  \\ since \: half \: life =  \frac{ ln(2) }{k}  \\ half \: life  =   \frac{ ln(2) }{0.096288}  \\ half \: life = 7.2 \: seconds

5 0
3 years ago
Read 2 more answers
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