An ideal diatomic gas at 80 k is slowly compressed adiabatically and reversibly to half its volume. The final temperature is 104.8k
<h3>Calculation of final temperature </h3>
The formula used for compression is:-
TV^(γ-1)=C
where;
T= temperature=80k
V=volume(given volume is half of its original volume i.e v/2)
γ=CP/CV= ( 7.R/2)/(5R/2)=7/5
C= constant
using the given values in the formula;
80 x V^[(7/5)-1]=T(final) (V/2)^[(7/5)-1]
80=T(final) x (V/V2)^(2/5)
80=T(final) x (1/2)^(2/5)
T(final)= 80 x (2)^2/5
T(final)= 80 x 1.31
final temperature =104.8k
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Answer:
0.504 M
Explanation:
Step 1: Write the balanced neutralization reaction
2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O
Step 2: Calculate the reacting moles of KOH
55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:
0.0552 L × 0.500 mol/L = 0.0276 mol
Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH
The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol
Step 4: Calculate the concentration of H₂SO₄
0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:
[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M
Carbon atoms are saturated with (surrounded by) Hydrogen atoms
a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
