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tekilochka [14]
4 years ago
8

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

om Saturn to the sun and then calculate it.
Physics
2 answers:
d1i1m1o1n [39]4 years ago
3 0
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
kari74 [83]4 years ago
3 0

Answer:

For astronomical objects, the time period can be calculated using:

T² = (4π²a³)/GM

where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)

Thus,

T² = a³

a = ∛(29.46²)

a = 0.67 AU

1 AU = 1.496 × 10⁸ Km

0.67 * 1.496 × 10⁸ Km

= 1.43 × 10⁹ Km

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Answer:

superscript

Explanation:

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An example is H2O . The 2 present represents two molecule of oxygen and its written as the subscript while Fe2+ in which the 2+ is written up is known as the superscript.

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At the surface, atmospheric pressure is 1.013 × 10^5 Pa. People can normally snorkel down to a depth of roughly one meter. What
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Answer:

1.01 × 10⁵ Pa  

Explanation:

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Pressure at a depth is given by :

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3 years ago
A uniform, thin, solid door has height 2.30 m, width 0.875 m, and mass 24.0 kg. (a) find its moment of inertia for rotation on i
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so A
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