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tekilochka [14]
4 years ago
8

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

om Saturn to the sun and then calculate it.
Physics
2 answers:
d1i1m1o1n [39]4 years ago
3 0
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
kari74 [83]4 years ago
3 0

Answer:

For astronomical objects, the time period can be calculated using:

T² = (4π²a³)/GM

where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)

Thus,

T² = a³

a = ∛(29.46²)

a = 0.67 AU

1 AU = 1.496 × 10⁸ Km

0.67 * 1.496 × 10⁸ Km

= 1.43 × 10⁹ Km

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  • Density (ρ) = 1000 Kg/m^3
  • Acceleration due to gravity (g) = 10 m/s^2
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<u>Answer</u><u>:</u>

<u>1000</u><u>0</u><u>0</u><u> </u><u>Pa</u>

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stellarik [79]

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2 x 2 x 2 x 3 x 7 = 168

Explanation:

Prime factors of 168: 2, 3 and 7

These are the factors of 168:  1,2,3,4,6,7,8,12,14,21,24,28,42,56,84,168. Only 2, 3 and 7 are prime numbers meaning that they are only divisible by themselves and 1. Therefore they are the prime factors.

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=> m * a_net = 200N - u mg

=> 10kg *a_net = 200N - 0.2*10*10

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