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ohaa [14]
2 years ago
8

A flare is launched from a boat. The height, , in meters, of the flare above the water is approximately modelled by the function

, where is the number of seconds after the flare is launched. How many seconds will it take for the flare to return to the water?
Physics
1 answer:
Tpy6a [65]2 years ago
6 0

Answer:

10 seconds

Explanation:

If the height is modeled by the function h(t)=-15t^{2} +150t, then the seconds it takes to reach the water (when the height equals 0) is modeled by the following.

0=-15t^{2} +150t\\0=-15t*(t-10)\\\\t=0\\t=10

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If the bonds in the reactants of Figure 7-3 contained 432 kJ of chemical energy and the bonds in the
Yuri [45]

Answer:

  • <u>The energy change would be 46kJ</u>
  • <u>The energy would be absorbed</u>

Explanation:

The <em>energy change </em>during a chemical reation, i.e. the reaction energy, is equal to the chemical energy stored in the<em> bonds of the products </em>less the chemical energy stored in the <em>bonds of the reactants</em>.

Hence:

  • <em>Energy change</em> = 478 kJ - 432kJ = 46kJ

The change is positive, this is, the chemical energy of the products is greater than the chemical energy of the reactants.

That corresponds to the second graph, where the level of the energy of the products in the graph is higher than the level of the energy of the reactants. Therefore, the conclusion is that the reaction <em>absorbed energy</em> and it is endothermic.

4 0
3 years ago
Whats the answer???????????
Leviafan [203]

Answer: Less than 4 ohms

Explanation:

We have three resistors with the following resistance:

R_{1}=4\Omega

R_{2}=6\Omega

R_{3}=8\Omega

Now, when the resistors are connected in parallel, the total resistance R is calculated as follows:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

Isolating R:

R=\frac{R_{1}R_{2}R_{3}}{R_{3}(R_{1}+R_{2})+R_{1}R_{2}}

Rewriting with th known values:

R=\frac{(4\Omega)(6\Omega)(8\Omega)}{8\Omega(4\Omega+6\Omega)+(4\Omega)(6\Omega)}

Finally:

R=1.84 \Omega

Hence, the correct option is less than 4 ohms.

4 0
2 years ago
What is the primary function of the small intestines
ikadub [295]

Digestion and Absorbtion

7 0
2 years ago
A coil spring with a spring rate of 0.28 N / cm is stretched with a force of 1.0 N to a length of 12.0 cm. Calculate the length
Jobisdone [24]

Answer:

2.3

Explanation:

firstly divide 1by12

4 0
2 years ago
Learning Goal: To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following gene
kaheart [24]

Answer:

so the transverse displacement is  0.089963 m

Explanation:

Given data

equation y(x,t)=Acos(kx−ωt)

speed  v = 9.00 m/s

amplitude A = 9.00 × 10^−2 m

wavelength λ   = 0.480 m

to find out

the transverse displacement

solution

we know

v = angular frequency / wave number

and

wave number = 2 \pi / λ  =  2 \pi / 0.480  = 13.0899 m^{-2}

angular frequency = v k

angular frequency = 9.00 × 13.0899

angular frequency = 117.8097 rad/sec = 118 rad/sec

so

equation y(x,t)=Acos(kx−ωt)

y(x,t)=9.00 × 10^−2 cos(13.0899 x−118t)

when x =0 and and t = 0

maximum y(x,t)= 9.00 × 10^−2 cos(13.0899 (0) − 118 (0))

maximum y(x,t)= 9.00 × 10^−2  m

and when x =  x = 1.59 m and t = 0.150 s

y(x,t)=9.00 × 10^−2 cos(13.0899 (1.59) −118(0.150) )

y(x,t)=9.00 × 10^−2 × (0.99959)

y(x,t) = 0.089963 m

so the transverse displacement is  0.089963 m

5 0
3 years ago
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