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galben [10]
3 years ago
6

Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbselectromagnetic wa

ves. Penetration into the ocean is greater at longer wavelengths, so the United States has radioinstallations that transmit at 76 Hz for submarine communications. What is the approximate wavelength of those extremelylow-frequency waves?A. 500 kmB. 1000 kmC. 2000 kmD. 4000 km
Physics
1 answer:
FrozenT [24]3 years ago
8 0

Answer:

D. 4000 km

Explanation:

f = Frequency of wave that is being transmitted = 76 Hz

\lambda = Wavelength of wave that is being transmitted

v = The velocity of electromagnetic waves through air = 3\times 10^8\ m/s

Velocity of a wave is given by

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{3\times 10^8}{76}\\\Rightarrow \lambda=3947368.42105\ m=3947.36842105 km\approx 4000\ km

Hence, the approximate wavelength of the waves is 4000 km

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You can just use basic trigonometry to solve for the x & y components.

<span>vector a = 10cos(30) i + 10sin(30) j = <5sqrt(3), 5></span>

vector b is only slightly harder because the angle is relative to vector a, and not the positive x-axis. Anyway, this just makes vector b with an angle of 135deg to the positive x-axis.

<span>vector b = 10cos(135) i + 10sin(135) j = <-5sqrt(2), 5sqrt(2)></span>

So now we can do the questions:

r = a + b

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The only correct statement on the list is choice-A./

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