The trick here is that there are two variables, Diameter of the coil and number of turns in it. So, in order to solve it, we will need two equations in D and N
Since we are making coil, formula for magnetic field will be B = μₒni/D
D = μₒni/B = 4π x 10^(-7) x (N) x (2.2) / (1.6)x10^(-3) = 1.7 x 10^(-3) x N = D
Another equation will be from the wire's length.
Total length = Circumference of one loop x No. of turns = πD x N = 2.2
We will eliminate N because we need D.
N = 2.2 / πD
Substitute in 1st equation.
1.7 x 10^(-3) x 2.2 / π = D^2
<span>
D = 0.034 m = 3.4 cm </span>
The centripetal acceleration of the space shuttle is
(0.9g)
Explanation:
The period of revolution of the space shuttle is

From the period, we can calculate the angular speed of the space shuttle, which is given by

Now we can calculate the centripetal acceleration of the space shuttle, given by

where
is the angular speed
is the distance of the shuttle from the Earth's centre (it is the sum of the Earth's radius, 6400 km, and of the altitude of the space shuttle, 300 km)
Substituting and solving, we find

And since
, this can be rewritten as

Learn more about centripetal acceleration:
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Well, I think the answer would be 4 meters because the speed is in meters per second and the frequency is 5 waves every 2 seconds.
Wavelength = Speed/Frequency
I think the frequency is 2.5 waves a second but that's not something I'm 100% sure about.
I hope this helps though.