Aye, I'm b0red so here's an easy one:
2 answers:
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Answer:
Rs = 0.02008 Ω = 20.08 mΩ
Explanation:
The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:
where,
= value of shunt resistance = ?
= current range of ammeter = 20 mA = 0.02 A
I = Required range of ammeter = 5 A
= Resistance of ammeter = 5 ohms
Therefore,
<u>Rs = 0.02008 Ω = 20.08 mΩ</u>
Hope this helps, if you need clarification i got you
