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anastassius [24]
4 years ago
6

PLEASE HELP FOR BRAINLIEST ANSWER!

Physics
2 answers:
Harman [31]4 years ago
7 0
I believe the answer is D hope this helped.
Alex787 [66]4 years ago
3 0
I believe the answer is the fourth one, hope this helps
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Just like the water cycle, rocks undergo changes of form in a rock cycle. A metamorphic rock can become an igneous rock, or a sedimentary rock can become a metamorphic one. Unlike the water cycle, you can’t see the process happening on a day-to-day basis. Rocks change very slowly under normal conditions, but sometimes catastrophic events like a volcanic eruption or a flood can speed up the process. So what are the three types of rocks, and how do they change into each other? Keep reading to find out!



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A tide with the least distance between low and high tides is called a(n) ____________________ tide.
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In a perfectly inelastic one-dimensional collision between two moving objects, what condition alone is necessary so that the fin
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What condition alone is necessary so that the final kinetic energy of the system is zero after the collision?

<u>Option(a). </u>The objects must have initial momenta with the same magnitude but opposite directions.

What is a momentum?

  • In Newtonian mechanics, linear momentum, translational momentum, or simply momentum is the product of the mass and velocity of an object.
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2 years ago
#4<br> HELP PLEASE!<br> Find Gravitational Potential Energy! <br> THANK YOU!
Scilla [17]

Answer:

\Delta GPE=-3.92\ 10^9\ J

Explanation:

<u>Gravitational Potential Energy</u>

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, g=9.8 m/sec^2

The mass of water is given as

m=8,000,000\ kg

The height above the rocks is h=50 m. Let's compute the GPE

GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)

GPE_1=3,920,000,000\ Joule

It should be expressed in scientific notation

GPE_1=3.92\ 10^9\ J

The GPE at the bottom, where h=0

GPE_2=0

The change of gravitational potential energy is:

\Delta GPE=GPE_2-GPE_1

\boxed{\Delta GPE=-3.92\ 10^9\ J}

8 0
3 years ago
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