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2 years ago

What is it plz help me!!

Physics

2 answers:

Darina [25.2K]2 years ago

7 0

Answer:

second one

Explanation:

riadik2000 [5.3K]2 years ago

6 0

Answer:

the compound transform protons into neutrons

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A 5 kg mass is accelerated at a rate of 2.5 m/s/s. what is the force that is exerted on this object

Sav [38]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5 × 2.5

We have the final answer as

Hope this helps you

3 0

3 years ago

What two gases in the atmosphere do animals and plants need to breathe and grow?

kenny6666 [7]

Answer: Explanation:

Plants and animals each produce the gases that the other needs to live. Plants need carbon dioxide—people and other animals exhale carbon dioxide as a waste product. People and other animals need oxygen—plants produce oxygen during an important process called photosynthesis, which turns the sun's energy into nutrients.

7 0

3 years ago

Read 2 more answers

A projectile, fired with unknown initial velocity, lands 20sec later on side of hill, 3000m away horizontally and 450m verticall

lorasvet [3.4K]

Explanation:

Given:

t = 20 seconds

x = 3000 m

y = 450 m

a) To find the vertical component of the initial velocity $v_{0y}$ , we can use the equation

$y = v_{0y}t - \frac{1}{2}gt^2$

Solving for $v_{0y}$ ,

$v_{0y} = \dfrac{y + \frac{1}{2}gt^2}{t}$

$\:\:\:\:\:\:\:=\dfrac{(450\:\text{m}) + \frac{1}{2}(9.8\:\text{m/s}^2)(20\:\text{s})^2}{(20\:\text{s})}$

$\:\:\:\:\:\:\:=120.5\:\text{m/s}$

b) We can solve for the horizontal component of the velocity $v_{0x}$ as

$x = v_{0x}t \Rightarrow v_{0x} = \dfrac{x}{t} = \dfrac{3000\:\text{m}}{20\:\text{s}}$

$v_{0x} = 150\:\text{m/s}$

4 0

3 years ago

A constant voltage is applied across a circuit element. If the resistance of the element is doubled, what is the effect on the p

miv72 [106K]

Answer:

The power dissipated is reduced by a factor of 2

Explanation:

The power dissipated by a resistor is given by:

$P=I^2 R$

where

I is the current

R is the resistance

by using Ohm's law, $I=\frac{V}{R}$ , we can rewrite the previous equation in terms of the voltage applied across the resistor (V):

$P=(\frac{V}{R})^2R=\frac{V^2}{R}$

In this problem, the resistance of the element is doubled, while the voltage is kept constant. So we have $R'=2R$ while V remains the same; substituting into the formula, we have:

$P'=\frac{V^2}{2R}=\frac{1}{2}\frac{V^2}{R}=\frac{P}{2}$

so, the power dissipated is reduced by a factor 2.

5 0

3 years ago

An L-C circuit containing an 82.0-mH inductor and a 1.60-nF capacitor oscillates with a maximum current of 0.800 A . Assuming th

ryzh [129]

Answer:

19.5 mJ

Explanation:

Assuming perfect components without resistance or losses, the circuit should oscillate indefinetly.

The circuit will have a natural pulsation of

$w = \frac{1}{\sqrt{L * C}} = \frac{1}{\sqrt{82e-3 * 1.6e-9}} = 87304 rad/s$

$f = \frac{w}{2\pi} = \frac{87304}{2\pi} = 13895 Hz$

$T = \frac{1}{f} = \frac{1}{13895} = 7.2 \mu s$

So, by the time t = 2.4 ms, 333.33 cycles would have passed

$\frac{2.4 ms}{7.2 \mu s} = \frac{2400 \mu s}{7.2 \mu s} = 333.33$

Therefore it would be at one third after the beginning of the cycle. The circuit would be in an equivalent state as t = (7.2 us)/3 = 2.4us

At t=0 the capacitor is fully charged, so the voltage is maximum and the current is 0. The current will increase towards a maximum of 800 mA at t=T/4, then decreas to 0 at t=T/2, decrease to -800 mA at 3T/4 and go back to 0 at t=T following a sine wave.

The equation of this sine wave would be

$I(t) = I0 * sin(w * t)$