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3 years ago

What is it plz help me!!

Physics

2 answers:

Darina [25.2K]3 years ago

7 0

Answer:

second one

Explanation:

riadik2000 [5.3K]3 years ago

6 0

Answer:

the compound transform protons into neutrons

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The electric potential is 40 V at point A near a uniformly charged sphere. At point B, 2.0 μm farther away from the sphere, the

KatRina [158]

Answer:

Explanation:

Potential at a point near a charge = Q / 4πε₀ R

where Q is charge given , R is distance of point from the charge .

Q / 4πε₀ R = 40

Electric field E at A = -dV / dR

= .16 x 10⁻³ / 2 x 10⁻⁶

= .08 x 10³

= 80 N/C

E = Q / 4πε₀ R²

80 = Q / 4πε₀ R x R

80 = 40 / R

R = 40 / 80

= .5 m .

4 0

3 years ago

Earth's oceans have an average depth of 3800 m, a total area of 3.63 × 108 km2, and an average concentration of dissolved gold o

ratelena [41]

To determine the mass of gold dissolved in oceans, we must first know the volume of the ocean in liters. To determine its volume, we multiply the area and the depth taking note of the consistency of units. The volume would be 1.38 x 10^18 cubic meters or 1.38x10^21 liters. Then,multiplying this to the concentration, the answer would be 8 x 10^12 grams or 8 billion kg.

3 0

4 years ago

Please help.

LenKa [72]

Mu wildest guess is c 1500

7 0

4 years ago

Read 2 more answers

A cylinder has a length of 3.23 cm, a diameter of 1.75 cm, and a mass of 65.3 grams. What is the density of the cylinder? Based

Firlakuza [10]

Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate density as follows:

density = mass / volume
density = 65.3 g / π(1.75/2 cm)^2 ( 3.23 cm )
density = 8.41 g/cm^3

6 0

4 years ago

Two loudspeakers, A and B are driven by the same amplifier

DedPeter [7]

<h3><u>Complete Question </u></h3>

Q)Two loudspeakers, A and B, are driven by the same amplifier as shown and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. Consider point Q along the extension of the line connecting the speakers, 1.00 m to the right of speaker B. Both speakers emit sound waves that travel directly from the speaker to point Q. a) What is the lowest frequency for which constructive interference occurs at point Q? b) What is the lowest frequency for which destructive interference occurs at point Q? The speed of sound wave is 344 m/s.

Answer:

lowest frequency is 172 Hz. for n = 1

lowest frequency is 86 Hz for n = 0

Explanation:

(a) Constructive interference takes place when the path difference is n where n=1,2,3 ...

frequency f = v /λn

= v n / d

= n ( 344 / 2 )

= n ( 172 ) Hz.

lowest frequency is 172 Hz

b)Destructive interference takes place when the path difference is n/2 x where n=1,3,5 ...

λ = 4/2n+1

for n = 0

λ = 4m

f = 344/4

f = 86 Hz.

lowest frequency is 86 Hz

3 0

4 years ago