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jeka94
2 years ago
13

What is it plz help me!!

Physics
2 answers:
Darina [25.2K]2 years ago
7 0

Answer:

second one

Explanation:

riadik2000 [5.3K]2 years ago
6 0

Answer:

the compound transform protons into neutrons

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A 5 kg mass is accelerated at a rate of 2.5 m/s/s. what is the force that is exerted on this object
Sav [38]

Answer:

<h2>12.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5 × 2.5

We have the final answer as

<h3>12.5 N</h3>

Hope this helps you

3 0
3 years ago
What two gases in the atmosphere do animals and plants need to breathe and grow?
kenny6666 [7]

Answer: Explanation:

Plants and animals each produce the gases that the other needs to live. Plants need carbon dioxide—people and other animals exhale carbon dioxide as a waste product. People and other animals need oxygen—plants produce oxygen during an important process called photosynthesis, which turns the sun's energy into nutrients.

7 0
3 years ago
Read 2 more answers
A projectile, fired with unknown initial velocity, lands 20sec later on side of hill, 3000m away horizontally and 450m verticall
lorasvet [3.4K]

Explanation:

Given:

t = 20 seconds

x = 3000 m

y = 450 m

a) To find the vertical component of the initial velocity v_{0y}, we can use the equation

y = v_{0y}t - \frac{1}{2}gt^2

Solving for v_{0y},

v_{0y} = \dfrac{y + \frac{1}{2}gt^2}{t}

\:\:\:\:\:\:\:=\dfrac{(450\:\text{m}) + \frac{1}{2}(9.8\:\text{m/s}^2)(20\:\text{s})^2}{(20\:\text{s})}

\:\:\:\:\:\:\:=120.5\:\text{m/s}

b) We can solve for the horizontal component of the velocity v_{0x} as

x = v_{0x}t \Rightarrow v_{0x} = \dfrac{x}{t} = \dfrac{3000\:\text{m}}{20\:\text{s}}

or

v_{0x} = 150\:\text{m/s}

4 0
3 years ago
A constant voltage is applied across a circuit element. If the resistance of the element is doubled, what is the effect on the p
miv72 [106K]

Answer:

The power dissipated is reduced by a factor of 2

Explanation:

The power dissipated by a resistor is given by:

P=I^2 R

where

I is the current

R is the resistance

by using Ohm's law, I=\frac{V}{R}, we can rewrite the previous equation in terms of the voltage applied across the resistor (V):

P=(\frac{V}{R})^2R=\frac{V^2}{R}

In this problem, the resistance of the element is doubled, while the voltage is kept constant. So we have R'=2R while V remains the same; substituting into the formula, we have:

P'=\frac{V^2}{2R}=\frac{1}{2}\frac{V^2}{R}=\frac{P}{2}

so, the power dissipated is reduced by a factor 2.

5 0
3 years ago
An L-C circuit containing an 82.0-mH inductor and a 1.60-nF capacitor oscillates with a maximum current of 0.800 A . Assuming th
ryzh [129]

Answer:

19.5 mJ

Explanation:

Assuming perfect components without resistance or losses, the circuit should oscillate indefinetly.

The circuit will have a natural pulsation of

w = \frac{1}{\sqrt{L * C}} = \frac{1}{\sqrt{82e-3 * 1.6e-9}} = 87304 rad/s

f = \frac{w}{2\pi} = \frac{87304}{2\pi} = 13895 Hz

T = \frac{1}{f} = \frac{1}{13895} = 7.2 \mu s

So, by the time t = 2.4 ms, 333.33 cycles would have passed

\frac{2.4 ms}{7.2 \mu s} = \frac{2400 \mu s}{7.2 \mu s} = 333.33

Therefore it would be at one third after the beginning of the cycle. The circuit would be in an equivalent state as t = (7.2 us)/3 = 2.4us

At t=0 the capacitor is fully charged, so the voltage is maximum and the current is 0. The current will increase towards a maximum of 800 mA at t=T/4, then decreas to 0 at t=T/2, decrease to -800 mA at 3T/4 and go back to 0 at t=T following a sine wave.

The equation of this sine wave would be

I(t) = I0 * sin(w * t)

I(T/3) = 0.8 * sin(w * T/3)

Since w = 2π/T

w * T = 2π

I(T/3) = 0.8 * sin(2 \pi /3) = 0.8 * 0.866 = 0.69 A

The current stored in an inductor is

E = \frac{1}{2} * L * I^2

E = \frac{1}{2} * 82e-3 * 0.69^2 = 0.0195 J = 19.5 mJ

6 0
3 years ago
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