Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope
Now, we know frequency is given by :
Therefore, the frequency of the second harmonic is 3 s⁻¹.
Answer: it's 12
Explanation:
Range is the difference between the highest and lowest numbers.
33-21=12
The ability of thermal energy to dissipate too quickly and not get concentrated makes it not suitable for doing work. In addition, thermal energy comes from the rapid movement of particles in which it is directly proportional. Therefore, the faster the particle movement, more heat or thermal energy is generated.
total mass M= 280 kg
<span>The coefficient of kinetic
friction between the sled and the snow = 0.080</span>
The sled acceleration a =0.65 m/s2
Initial speed u = 0
cruising speed v = 15 km/h.
= 15 (1000m/3600s) = 4.166
m/s
(A ). The team's maximum
power output during the acceleration phase P = ?
Net force Ma = Applied force
- fricitonal force
<span>= F - Mg</span>
<span>From this F = Ma +Mg</span>
<span>= M(a+g)</span>
= 280(0.65+(0.08x9.8))
= 401.52 N
So, P = Fv
= 401.52 x 4.166
= 1,672.7323 W
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