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klio [65]
3 years ago
5

Plz explain the answers with steps and a little bit of explanation. I really need the answers for my exam tomorrow! Please help

me!

Physics
1 answer:
DochEvi [55]3 years ago
7 0
Here's what you need to memorize for your exam tomorrow.

Distance = (speed) x (time) .

That's it. Memorize it.

-- If the question wants you to find speed, use it exactly in that form.

-- If the question wants you to find speed, then divide each side by (time)
and it says

. Time = (distance) / (speed) .

-- If the question wants you to find time, then divide each side by speed,
and it says

. Time = (distance) / (speed) .

So if you memorize that one equation ... Distance = (speed) x (time) ...
you can solve ANY problem to find distance, speed, or time.

On the sheet in the picture . . . . .

#2). The question is "How long ?". That's TIME that you have to find.
Use the equation in the form of

. TIME = (distance) / (speed)

. = (60 km) / (48 km/h)

. = 1.25 hours .

#3). This one wants you to find SPEED. Use the equation in the form of

. SPEED = (distance) / (time)

but be careful. The time has to be in hours. 55 minutes = 55/60 of an hour.

. SPEED = (distance) / (time)

. = (60 km) / (55/60 hour)

. = (60 x 60 km) / (55 hour)

. = 65.45 km/hr .

#4). This one wants you to find TIME. (It says "How long ?".)

It's two trips, so you have to find the time for each trip.

First trip: TIME = (distance)/(speed) = (24 km)/(65 km/hr) = 0.369 hr

Second trip: TIME = (distance)/(speed) = (50 km)/(80 km/hr) = 0.625 hr

Total time for both trips = (0.369 hr) + (0.625 hr) = 0.994 hour
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alexandr402 [8]
Option A is the correct answer.
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Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.
Marina CMI [18]

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A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-
Lilit [14]

Answer:

The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

Explanation:

Given that,

Velocity of ship = 2.00 m/s due south

Velocity of boat = 5.60 m/s due north

Angle = 19.0°

We need to calculate the component

The velocity of the ship in term x and y coordinate

v_{s_{x}}=0

v_{s_{y}}=2.0\ m/s

The velocity of the boat in term x and y coordinate

For x component,

v_{b_{x}}=v_{b}\cos\theta

Put the value into the formula

v_{b_{x}}=5.60\cos19

v_{b_{x}}=5.29\ m/s

For y component,

v_{b_{y}}=v_{b}\sin\theta

Put the value into the formula

v_{b_{y}}=5.60\sin19

v_{b_{y}}=1.82\ m/s

We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat

For x component,

v_{sb_{x}}=v_{s_{x}}-v_{b_{x}}

Put the value into the formula

v_{sb_{x}=0-5.29

v_{sb}_{x}=-5.29\ m/s

For y component,

v_{sb_{y}}=v_{s_{y}}-v_{b_{y}}

Put the value into the formula

v_{sb_{x}=2.-1.82

v_{sb}_{x}=0.18\ m/s

Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

7 0
3 years ago
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field
Xelga [282]

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

B = \mu_{0}nI

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

B_{1} = \mu_{0}n_{1}I  ------------------- equation 1

For Solenoid 2:

n₂ = 6n₁

Therefore,

B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I  ----------------- equation 2

Diving equation 1 and equation 2:

\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6

Hence, the correct option is:

<u>6</u>

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