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11111nata11111 [884]
3 years ago
12

3(x+5) = x + 19 solution please

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0
X=2
Distribute 3 into parentheses. Then subtract 15 from both sides which gives you 3x=x+4.
Subtract x from both sides which gives you 2x=4. Divide by 2 on both sides thus giving you x=2.
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Please find the value of x and y.​
Sophie [7]

Answer:

x = 11

y = 3

Step-by-step explanation:

4y+1=6y-5

-4y   -4y

+1   =2y-5

+5       +5

  6/2=2y/2

      3=y

2x-4=  18

  +4    +4

2x/2 = 22/2

      x=11

7 0
3 years ago
What is an equation of the line that passes through the points (0, -4) and (-4, 6)?
olganol [36]

Answer:

The equation of the line is.

y=-\frac{5}{2}x-4

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points (x_{1},y_{1}) and (x_{2},y_{2}) is.

\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}

\frac{x}{-4}=\frac{y+4}{6+4}

-\frac{x}{4}=\frac{y+4}{10}

-\frac{10x}{4}=y+4

-10x=4(y+4)

-10x=4y+16

4y=-10x-16

The above equation is divided by 2 both sides.

2y=-5x-8

y=-\frac{5}{2}x-4

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is y=-\frac{5}{2}x-4

8 0
2 years ago
Draw a rectangle with an area of 42 square units
Butoxors [25]
We know, Area = Length * Width

So, with area 42, dimensions could be: 1 * 42
2 * 21
3 * 14
6 * 7

Just draw the lines with that measures, two pair of two equal opposite lines.

Hope this helps!

6 0
3 years ago
Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an
Gelneren [198K]

Answer:

(a) P (<em>Z</em> < 2.36) = 0.9909                    (b) P (<em>Z</em> > 2.36) = 0.0091

(c) P (<em>Z</em> < -1.22) = 0.1112                      (d) P (1.13 < <em>Z</em> > 3.35)  = 0.1288

(e) P (-0.77< <em>Z</em> > -0.55)  = 0.0705       (f) P (<em>Z</em> > 3) = 0.0014

(g) P (<em>Z</em> > -3.28) = 0.9995                   (h) P (<em>Z</em> < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, X \sim N (\mu, \sigma^{2}), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean.  The <em>z</em>-scores are standardized scores.

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

(a)

Compute the value of P (<em>Z</em> < 2.36) as follows:

P (<em>Z</em> < 2.36) = 0.99086

                   ≈ 0.9909

Thus, the value of P (<em>Z</em> < 2.36) is 0.9909.

(b)

Compute the value of P (<em>Z</em> > 2.36) as follows:

P (<em>Z</em> > 2.36) = 1 - P (<em>Z</em> < 2.36)

                   = 1 - 0.99086

                   = 0.00914

                   ≈ 0.0091

Thus, the value of P (<em>Z</em> > 2.36) is 0.0091.

(c)

Compute the value of P (<em>Z</em> < -1.22) as follows:

P (<em>Z</em> < -1.22) = 0.11123

                   ≈ 0.1112

Thus, the value of P (<em>Z</em> < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < <em>Z</em> > 3.35) as follows:

P (1.13 < <em>Z</em> > 3.35) = P (<em>Z</em> < 3.35) - P (<em>Z</em> < 1.13)

                            = 0.99960 - 0.87076

                            = 0.12884

                            ≈ 0.1288

Thus, the value of P (1.13 < <em>Z</em> > 3.35)  is 0.1288.

(e)

Compute the value of P (-0.77< <em>Z</em> > -0.55) as follows:

P (-0.77< <em>Z</em> > -0.55) = P (<em>Z</em> < -0.55) - P (<em>Z</em> < -0.77)

                                = 0.29116 - 0.22065

                                = 0.07051

                                ≈ 0.0705

Thus, the value of P (-0.77< <em>Z</em> > -0.55)  is 0.0705.

(f)

Compute the value of P (<em>Z</em> > 3) as follows:

P (<em>Z</em> > 3) = 1 - P (<em>Z</em> < 3)

             = 1 - 0.99865

             = 0.00135

             ≈ 0.0014

Thus, the value of P (<em>Z</em> > 3) is 0.0014.

(g)

Compute the value of P (<em>Z</em> > -3.28) as follows:

P (<em>Z</em> > -3.28) = P (<em>Z</em> < 3.28)

                    = 0.99948

                    ≈ 0.9995

Thus, the value of P (<em>Z</em> > -3.28) is 0.9995.

(h)

Compute the value of P (<em>Z</em> < 4.98) as follows:

P (<em>Z</em> < 4.98) = 0.99999

                   ≈ 0.9999

Thus, the value of P (<em>Z</em> < 4.98) is 0.9999.

**Use the <em>z</em>-table for the probabilities.

3 0
2 years ago
A student is given the rectangle and the square shown. The student states that the two figures have the
VladimirAG [237]

Answer:

correct

Step-by-step explanation:

The perimeter is the sum of the sides.

Rectangle ( opposite sides are congruent ), thus

perimeter = 2x + 2(x + 18) = 2x + 2x + 36 = 4x + 36

Square ( sides are congruent ), thus

perimeter = 4(x + 9) = 4x + 36

The perimeters are the same, so the student is correct

5 0
3 years ago
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