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Leviafan [203]
3 years ago
7

PLEASE HELP IN ONE MINUTE

Physics
1 answer:
Greeley [361]3 years ago
4 0
I think it’s 8 hours. I’m sorry if I’m wrong.
I just did 400 divided by 50
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A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the neg
Natali5045456 [20]

Answer: Vf = 2,400,000 m/s

Explanation:

1) The only relevant force is the electrostatic force

2) The formula for the electrostatic force is F = E×q

Where E is the electric field and q is the magnitude of the charge.

3) Since the electric field is the same in both cases, and the charge of the protons and electrons have the same magnitude, you can state that the magntitude of the electric forces acting in both proton and electron are the same

4) Fe = Fp (Fe stands for force on the electron and Fp stands for force on the proton).

5) Using second law of Newton, Force = mass × acceleration

Fe = Me × Ae (Me is mass of the electron, and Ae is acceleration of the electron)

Fp = Mp × Ap (Mp is mass of the proton, and Ap is acceleration of the proton)

⇒Me × Ae = Mp × Ap

⇒ Ae = Mp × Ap / Me

6) Now, state the equations for the velocity in uniformly accelerated motion:

i) Vf² = Vo² + 2ad

Vo² = 0 for both cases, and d is the same distance.

⇒ Vf² = 2ad

ii) For the proton Vf² = 2(Ap)(d) ⇒ Ap = Vf² / (2d)

⇒ Ap = (55,000 m/s)² / (2d)

iii) For the electron Vf² = 2(Ae)² (2d)

iv) Using Ae = Mp × Ap / Me (found prevously):

Vf² = Mp × (55,000 m/s)² / (2d) × (2d) / Me

⇒ Vf² = Mp × (55,000 m/s)² / Me

Taking square root in both sides:

⇒ Vf = 55,000 m/s × √ [Mp / Me]

7) These are the values for the masses of a proton and an electron:

Mp = 1.67 × 10⁻²⁷ kg

Me = 9.11×10⁻³¹ kg

8) Replace and compute:

Vf = 55,000 m/s × √ [ 1.67 × 10⁻²⁷ kg / 9.11×10⁻³¹ kg] = 2,354,841.8 m/s

Round to two significan digits: Vf = 2,400,000 m/s

5 0
3 years ago
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A hot-air balloonist, rising vertically with a constant speed of 5.00 m/s releases a sandbag at the instant the balloon is 40.0
iren [92.7K]

Answer:

Y = 40.94m

Explanation:

The initial speed of the sandbag is the same as the balloon and so is its position, so:

Y = Yo + Vo*t-\frac{g*t^2}{2}

Replacing these values:

Yo = 40m     Vo = 5m/s     g = 9.81m/s^2     t = 0.25s

We get the position of the sandbag:

Y = 40+5*(0.25)-\frac{9.81*(0.25)^2}{2}

Y = 40.94m

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What is one of the hardest tasks for researchers ?
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To know if their research is correct or matches their hypothesis.
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Water is able to dissolve many substances because of its
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It can dissolve many substances because 1. Polarity of water molecule. 2. Exceptional hydrogen bonding ability (Not in list)
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What<br> A moving object always has energy in its
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The answer is a cell I think hope it helps sorry if wrong
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