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Lera25 [3.4K]
3 years ago
13

Oo hi granger ru online here i have a doubt in physics . ​

Physics
1 answer:
NISA [10]3 years ago
4 0

Answer:

.

Explanation:

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what is the magnitude of g at a height above earth surface where free fall acceleration equal 6.5m/s2
ZanzabumX [31]
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.
8 0
3 years ago
An object moves in a circle with a period of 0.025 hours. What is its frequency in Hz?
Sedaia [141]

Answer:

40 Hz

Explanation:

f = 1/T = 1 / 0.025 = 40 Hz

7 0
3 years ago
Political scientists use political models to describe which of the following? a. political spectrum b. political shift c. politi
aniked [119]

Answer:

D

Explanation:

Political scientists use political models to describe the political climate, which is an aggregate mood or opinion of a political society at a point in time.

8 0
3 years ago
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Water at the top of a slope has potential energy. true or false
ASHA 777 [7]
<span>The statement is TRUE. Water does have potential energy at the top of a slope. The reason why is that potential energy is energy possessed by a body based on its position relative to a zero point. In this case, water at the top of the slope is at an elevation above ground (zero point). The energy is not kinetic (moving) energy since the water is not moving.</span>
8 0
4 years ago
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Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through
bekas [8.4K]
We know that arc length (x(t)) is given with the following formula:
x(t)=\theta(t) r
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}
When we plug this back into the first equation we get:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\
We must solve this quadratic equation.
The final solution is:
\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\&#10;x(t)=\theta r_0\\&#10;\theta(t)=\frac{x(t)}{r_0}

8 0
4 years ago
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