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3 years ago

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Calcium chloride and silver nitrate react to form a precipitate of silver chloride in a solution of calcium nitrate. This is an

example of?
A. a combustion reaction
B. a Displacement reaction
C. a Decomposition reaction
D. Polymerization

1 answer:

rewona [7]3 years ago

8 0

B a Displacement reaction.

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Calculate the amount of heat energy in KJ required to convert 45.0 g of ice at -15.5'C to steam at 124.0°C. (Cwater 118 Jig'c, G

dangina [55]

Answer : The enthalpy change or heat required is, 139.28775 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-15.5^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(124^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat required = ?

m = mass of water = 45 g

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

n = number of moles of water = $\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{45g}{18g/mole}=2.5mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[45g\times 4.18J/gK\times (0-(-15.5))^oC]+2.5mole\times 6010J/mole+[45g\times 2.09J/gK\times (100-0)^oC]+2.5mole\times 40670J/mole+[45g\times 1.84J/gK\times (124-100)^oC]$

$\Delta H=139287.75J=139.28775KJ$ (1 KJ = 1000 J)

Therefore, the enthalpy change is, 139.28775 KJ

3 0

3 years ago

Definition of neutral

iren2701 [21]

Not helping or supporting either side of the argument

8 0

3 years ago

Read 2 more answers

Acetylcholine is broken down to acetate and choline by an enzyme calledacetylcholinesterase. Low levels of acetylcholine in the

zlopas [31]

Answer:

a. A non-competitive inhibitor of acetylcholinesterase.

Explanation:

The enzyme acetylcholinesterase breaks the molecule of acetylcholine, so to maintain the levels of this substance higher in the brain, the medication must act directly in the enzyme.

An enzyme can be inactivated by higher temperatures, changes in pH and changes in the osmotic pressure, but these things would probably damage other enzymes in the brain. So, the medication must be an inhibitor of acetylcholinesterase. It would be selective and would stop the actions of the enzyme.

But, this inhibitor can't be competitive because if this happens, it would break the acetylcholine, and wouldn't solve the problem.

4 0

3 years ago

According to ______Law, if the temperature remains constant, doubling the pressure will _______the volume of the gas.

iren2701 [21]

Answer: According to Boyle's Law, if the temperature remains constant, doubling the pressure will halve the volume of the gas.

Explanation:

5 0

3 years ago

These equations below show two standard reduction potentials. Fe3+(aq) + e– Fe2+(aq) Eo = +0.77 Cu2+(aq) + 2e– Cu(s) Eo = +0.34

IgorC [24]

<h3>Answer:</h3>

= +0.43 V

<h3>Explanation:</h3>

The two standard reduction potentials are;

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E₀ = +0.77 V

Cu²⁺(aq) + 2e⁻ → Cu(s) E₀ = +0.34 V

The overall reaction is;

Fe³⁺(aq) + Cu(s) → Fe²⁺(aq) + Cu²⁺(aq)

To calculate the standard cell potential of the overall reaction, we use the equation;

Ecell = E redu, cathode - E red, anode

From the reaction; Copper lost electrons to form copper ions (Cu²⁺) (Oxidation) while Fe³⁺ gained electrons to form Fe²⁺ (reduction)

Therefore;

E cell = + 0.77 v - (+0.34 v)

= + 0.43 V

Hence, the standard cell potential of the overall reaction is +0.43 V

6 0

3 years ago