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lana [24]
3 years ago
14

List what instrument each of the following are measured with:

Chemistry
1 answer:
Vika [28.1K]3 years ago
5 0

wind can be measured using a tool called an anemometer

Atmospheric pressure is commonly measured with a barometer

temperature is measured with a thermometer

Precipitation is measured by using a rain gauge.

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Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu
nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,  

Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

E^0_{[Pb^{2+}/Pb]}=-0.13V

E^0_{[Cu^{2+}/Cu]}=+0.34V

E^0_{cell}=E^0_{cathode}-E^0_{anode}

E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}

E^0_{cell}=-0.13V-(0.34V)=-0.47V

Now we have to calculate the standard Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0
3 years ago
To arrive at the number of hydrogen atoms, What can be said about the relationship between the number of hydrogen atoms and the
Semenov [28]

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nothing shsheysyeggehssl

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3 years ago
Number of stable isotopes in Hydrogen?
kari74 [83]
3.
protium (A = 1), deuterium (A = 2), and tritium (A = 3).
5 0
2 years ago
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What is the molarity of a solution that contains 1.1 moles of lithium in 0.5 liters of solution?
cluponka [151]
0.5 litres contain 1.1 moles
therefore 1 litre will have= 1*1.1/0.5
             molarity=2.2M
8 0
3 years ago
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Find the final pressure of gas at 150k. If the pressure of the gas is 210 kPa at 120 K.
katrin [286]
Since the volume is constant,
p1/t = p2/ t
210/120 = p2/150
p2= 262.5kpa
4 0
3 years ago
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