Question

A block with a mass M = 4.85 kg is resting on a slide that has a curved surface. There is no friction. The speed of the block after it has slid along the slide sufficiently far for its vertical drop to be 19.6 m is:__________a. 19.6 m/s b. 384 m/s c. 93 m/s d. 43.2 m/s e. The problem cannot be solved because the shape of the curved slide is not given.

Answer 1

Answer:

The correct option is a

Explanation:

From the question we are told that

   The mass of the block is  $m = 4.84 \ kg$

    The height of the vertical  drop is $h = 19.6 \ m$

Generally from the law of energy conservation , the potential energy at the top  of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

        $PE = KE$

i.e     $m * g * h = \frac{1}{2} * m * v^2$

=>    $gh = 0.5 v^2$

=>   $v = \sqrt{\frac{9.8 * 19.6}{0.5 } }$

=>    $v = 19.6 \ m/s$